#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#define R(a,b,c) for(register int a = (b); a <= (c); ++ a)
#define nR(a,b,c) for(register int a = (b); a >= (c); -- a)
#define Max(a,b) ((a) > (b) ? (a) : (b))
#define Min(a,b) ((a) < (b) ? (a) : (b))
#define Fill(a,b) memset(a, b, sizeof(a))
#define Swap(a,b) a^=b^=a^=b
#define ll long long
#define ON_DEBUG
#ifdef ON_DEBUG
#define D_e_Line printf("
----------
")
#define D_e(x) cout << #x << " = " << x << endl
#define Pause() system("pause")
#else
#define D_e_Line ;
#endif
struct ios{
template<typename ATP>ios& operator >> (ATP &x){
x = 0; int f = 1; char c;
for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-') f = -1;
while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
x*= f;
return *this;
}
}io;
using namespace std;
#define stone 2
#define spider 3
#define endPlace 9
const int N = 37;
int n, m;
struct MAP{
int x_1, y_1, x_2, y_2, step;
}u, v;
#include<queue>
queue<MAP>q;
int mp[N][N];
int ans = 0x3f3f3f3f;
int walk_1[4][2]={{1,0},{0,1},{-1,0},{0,-1}};
int walk_2[4][2]={{1,0},{0,-1},{-1,0},{0,1}};
int vis[N][N][N][N];
inline void BFS(){
vis[u.x_1][u.y_1][u.x_2][u.y_2] = true;
q.push(u);
while(!q.empty()){
u = q.front();
q.pop();
if(mp[u.x_1][u.y_1] == endPlace && mp[u.x_2][u.y_2] == endPlace){
ans = u.step;
return;
}
R(i,0,3){
v.x_1 = u.x_1 + walk_1[i][0];
v.y_1 = u.y_1 + walk_1[i][1];
v.x_2 = u.x_2 + walk_2[i][0];
v.y_2 = u.y_2 + walk_2[i][1];
v.step = u.step + 1;
if(v.x_1 < 1 || v.x_2 < 1 || v.y_1 < 1 || v.y_2 < 1 || v.x_1 > n || v.x_2 > n || v.y_1 > m || v.y_2 > m) continue;
if(mp[v.x_1][v.y_1] == stone) v.x_1 = u.x_1, v.y_1 = u.y_1;
if(mp[v.x_2][v.y_2] == stone) v.x_2 = u.x_2, v.y_2 = u.y_2;
if(mp[v.x_1][v.y_1] == spider || mp[v.x_2][v.y_2] == spider) continue;
if(vis[v.x_1][v.y_1][v.x_2][v.y_2]) continue;
vis[v.x_1][v.y_1][v.x_2][v.y_2] = 1;
q.push(v);
}
}
}
int st[2][2];
int main(){
io >> n >> m;
R(i,1,n){
char str[57];
scanf("%s", str + 1);
R(j,1,m){
switch(str[j]){
case '#' :{
mp[i][j] = stone;
break;
}
case 'X' :{
mp[i][j] = spider;
break;
}
case 'T' :{
mp[i][j] = endPlace;
break;
}
case 'G' :{
mp[i][j] = 7;
st[0][0] = i, st[0][1] = j;
break;
}
case 'M' :{
mp[i][j] = 8;
st[1][0] = i, st[1][1] = j;
break;
}
case '.' :{
mp[i][j] = 1;
break;
}
}
}
}
u = (MAP){st[0][0], st[0][1], st[1][0], st[1][1], 0};
BFS();
if(ans == 0x3f3f3f3f){
printf("no");
}
else{
printf("%d", ans);
}
return 0;
}