Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1.
The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
public int threeSumClosest(int[] nums, int target) {
int length = nums.length;
Arrays.sort(nums);
int diff=Integer.MAX_VALUE;
int sumclosest=Integer.MAX_VALUE;
for (int i = 0; i < length-2; i++) {
if(i>0&&nums[i]==nums[i-1]){
continue;
}
int head = i+1;
int tail = length-1;
while (head<tail){
int tmp = nums[i]+nums[head]+nums[tail];
int newdiff = Math.abs(tmp-target);
if (diff>newdiff){
diff = newdiff;
sumclosest = tmp;
}
if (tmp<target){
head++;
}
else if (tmp>target){
tail--;
}
else {
int k=head+1;
while (k<tail&&nums[k]==nums[k-1]){
k++;
}
head = k;
int l=tail-1;
while (l>head&&nums[l]==nums[l+1]){
l--;
}
tail = l;
}
}
}
return sumclosest;
}