Populating Next Right Pointers in Each Node II

Follow up for problem "Populating Next Right Pointers in Each Node".

What if the given tree could be any binary tree? Would your previous solution still work?

Note:

• You may only use constant extra space.

 

For example,
Given the following binary tree,

         1
       /  
      2    3
     /     
    4   5    7

 

After calling your function, the tree should look like:

         1 -> NULL
       /  
      2 -> 3 -> NULL
     /     
    4-> 5 -> 7 -> NULL
思路：这道题和Populating Next Right Pointers in Each Node思路差不多，就是现在不是完全二叉树，不过一样适用。

/**
 * Definition for binary tree with next pointer.
 * struct TreeLinkNode {
 *  int val;
 *  TreeLinkNode *left, *right, *next;
 *  TreeLinkNode(int x) : val(x), left(NULL), right(NULL), next(NULL) {}
 * };
 */
class Solution {
public:
    void connect(TreeLinkNode *root) {
        queue<TreeLinkNode*> qroot;
        if(root==NULL)
            return;
        qroot.push(root);
        qroot.push(NULL);
        while(qroot.size())
        {
            TreeLinkNode* currentNode=qroot.front();
            qroot.pop();
            if(currentNode)
            {
                currentNode->next=qroot.front();
                if(currentNode->left)
                    qroot.push(currentNode->left);
                if(currentNode->right)
                    qroot.push(currentNode->right);
            }
            else
            {
                if(qroot.size())
                {
                    qroot.push(NULL);
                }
            }
            
        }
    }
};