【dijkstra】【次短路】【fread】hdu6181 Two Paths

题意：给你一张简单无向图，问你1到n的次短路。注意，可以不是简单路径。

存个次短路板子，原理还是挺简单，直接看代码吧。然后这份代码还是个fread的示例用法。

#include<cstdio>
#include<queue>
#include<algorithm>
#include<cstring>
using namespace std;
const int BUF=60000000;
char Buf[BUF],*buf=Buf;
inline void read(int&a){for(a=0;*buf<48;buf++);while(*buf>47)a=a*10+*buf++-48;}
#define N 100000+10
#define INF 1000000000000000ll
typedef long long ll;
typedef pair<ll, int> Point;
priority_queue<Point,vector<Point>,greater<Point> >Heap;
int n;
ll dist[N],dist2[N];
int e,first[N],nex[N<<1],v[N<<1],w[N<<1];
void AddEdge(int U, int V,int W){
	v[++e]=V;
	w[e]=W;
	nex[e]=first[U];
	first[U]=e;
}
int m,T;
int main()
{
	int x,y,z;
//	freopen("1011.in","r",stdin);
	fread(Buf,1,BUF,stdin);
	read(T);
	for(;T;--T){
		read(n); read(m);
		e=0;
		memset(first,0,sizeof(first));
		for(int i=1;i<=m;++i){
			read(x); read(y); read(z);
			AddEdge(x-1,y-1,z);
			AddEdge(y-1,x-1,z);
		}
		fill(dist,dist+n,INF);
		fill(dist2,dist2+n,INF);
		dist[0]=0;
		Heap.push(Point(0,0));
		while(!Heap.empty()){
			Point o=Heap.top(); Heap.pop();
			int U=o.second;
			ll d=o.first;
			if(dist2[U]<d){
				continue;
			}
			for(int i=first[U];i;i=nex[i]){
				ll d2=d+(ll)w[i];
				if(dist[v[i]]>d2){
					swap(dist[v[i]],d2);
					Heap.push(Point(dist[v[i]],v[i]));
				}
				if(dist2[v[i]]>d2 && dist[v[i]]<d2){
					dist2[v[i]]=d2;
					Heap.push(Point(dist2[v[i]],v[i]));  
				}
			}
		}
		printf("%lld
",dist2[n-1]); 
	}
    return 0;
}