mysql 多表查询
创建2个对应的表
create table department( id int, name varchar(20) ); create table employee( id int primary key auto_increment, name varchar(20), sex enum('male','female') not null default 'male', age int, dep_id int ); --插入数据 insert into department values (200,'技术'), (201,'人力资源'), (202,'销售'), (203,'运营'); insert into employee(name,sex,age,dep_id) values ('egon','male',18,200), ('alex','female',48,201), ('wupeiqi','male',38,201), ('yuanhao','female',28,202), ('liwenzhou','male',18,200), ('jingliyang','female',18,204) ;
1. 连表查询
inner join 内连接 只连接匹配的行
left join 左连接 优先显示左表全部记录
right join 右连接 优先显示右表全部记录
union 全外连接 显示左右两个表全部记录
select 字段列表 from tb1 inner|left|right join tb2 on tb1.id=tb2=id
1) inner join
select * from department d inner join employee e on d.id=e.dep_id;
select * from department d inner join employee e where d.id=e.dep_id;
+------+--------------+----+-----------+--------+------+--------+ | id | name | id | name | sex | age | dep_id | +------+--------------+----+-----------+--------+------+--------+ | 200 | 技术 | 1 | egon | male | 18 | 200 | | 201 | 人力资源 | 2 | alex | female | 48 | 201 | | 201 | 人力资源 | 3 | wupeiqi | male | 38 | 201 | | 202 | 销售 | 4 | yuanhao | female | 28 | 202 | | 200 | 技术 | 5 | liwenzhou | male | 18 | 200 | +------+--------------+----+-----------+--------+------+--------+
2) left join
select * from department d left join employee e on d.id=e.dep_id;
+------+--------------+------+-----------+--------+------+--------+ | id | name | id | name | sex | age | dep_id | +------+--------------+------+-----------+--------+------+--------+ | 200 | 技术 | 1 | egon | male | 18 | 200 | | 201 | 人力资源 | 2 | alex | female | 48 | 201 | | 201 | 人力资源 | 3 | wupeiqi | male | 38 | 201 | | 202 | 销售 | 4 | yuanhao | female | 28 | 202 | | 200 | 技术 | 5 | liwenzhou | male | 18 | 200 | | 203 | 运营 | NULL | NULL | NULL | NULL | NULL | +------+--------------+------+-----------+--------+------+--------+
3) right join
select * from employee e right join department d on d.id=e.dep_id;
+------+-----------+--------+------+--------+------+--------------+ | id | name | sex | age | dep_id | id | name | +------+-----------+--------+------+--------+------+--------------+ | 1 | egon | male | 18 | 200 | 200 | 技术 | | 2 | alex | female | 48 | 201 | 201 | 人力资源 | | 3 | wupeiqi | male | 38 | 201 | 201 | 人力资源 | | 4 | yuanhao | female | 28 | 202 | 202 | 销售 | | 5 | liwenzhou | male | 18 | 200 | 200 | 技术 | | NULL | NULL | NULL | NULL | NULL | 203 | 运营 | +------+-----------+--------+------+--------+------+--------------+
4) union
select * from employee left join department on employee.dep_id = department.id union select * from employee right join department on employee.dep_id = department.id;
+------+------------+--------+------+--------+------+--------------+ | id | name | sex | age | dep_id | id | name | +------+------------+--------+------+--------+------+--------------+ | 1 | egon | male | 18 | 200 | 200 | 技术 | | 5 | liwenzhou | male | 18 | 200 | 200 | 技术 | | 2 | alex | female | 48 | 201 | 201 | 人力资源 | | 3 | wupeiqi | male | 38 | 201 | 201 | 人力资源 | | 4 | yuanhao | female | 28 | 202 | 202 | 销售 | | 6 | jingliyang | female | 18 | 204 | NULL | NULL | | NULL | NULL | NULL | NULL | NULL | 203 | 运营 | +------+------------+--------+------+--------+------+--------------+
--用来替换 or 、in() SELECT * FROM world.city WHERE countrycode IN ('CHN','JPN'); 改写为: SELECT * FROM world.city WHERE countrycode ='CHN' union SELECT * FROM world.city WHERE countrycode ='JPN';
二 子查询
1:子查询是将一个查询语句嵌套在另一个查询语句中。
2:内层查询语句的查询结果,可以为外层查询语句提供查询条件。
3:子查询中可以包含:IN、NOT IN、ANY、ALL、EXISTS 和 NOT EXISTS等关键字
4:还可以包含比较运算符:= 、 !=、> 、<等
二 练习
1.以内连接的方式查询employee和department表,并且employee表中的age字段值必须大于25,即找出年龄大于25岁的员工以及员工所在的部门
select employee.name, department.name from employee inner join department on employee.dep_id=department.id where employee.age > 25;
2.以内连接的方式查询employee和department表,并且以age字段的升序方式显示
select * from employee inner join department on employee.dep_id=department.id order by age;
3. 带in关键字的子查询
①查询平均年龄在25岁以上的部门名
select * from department where id in (select dep_id from employee group by dep_id having avg(age) > 25);
②查看技术部员工姓名
select * from employee where dep_id = (select id from department where name="技术"); select * from employee where dep_id in (select id from department where name="技术");
③查看不足1人的部门名
select * from department where id not in (select dep_id from employee group by dep_id);
4 带比较运算符的子查询
①查询大于所有人平均年龄的员工名与年龄
select * from employee where age >(select avg(age) from employee);
②查询大于部门内平均年龄的员工名、年龄
select t1.name,t1.age from employee t1 inner join (select dep_id,avg(age) avg_age from employee group by dep_id) t2 on t1.dep_id = t2.dep_id where t1.age > t2.avg_age;