做一个倒计时的功能,天,时,分 /时,分,秒

如果有天的存在,就是天,时,分,如果没有天的存在,就是时,分,秒

<p class="fishqcTryProduct-value" style="margin-top: .5rem">据开抢:
     <span class="fishqc-padding" ms-visible="el.days!='0'||el.days0!='0'"><span>{{el.days0}}</span><span>{{el.days}}</span></span><span ms-visible="el.days!='0'||el.days0!='0'">天</span>
     <span class="fishqc-padding"><span>{{el.hours1}}</span><span>{{el.hours2}}</span></span>时
     <span class="fishqc-padding"><span>{{el.minutes1}}</span><span>{{el.minutes2}}</span></span>分
     <span class="fishqc-padding" ms-visible="el.days=='0'&&el.days0=='0'"><span>{{el.seconds1}}</span><span>{{el.seconds2}}</span></span><span ms-visible="el.days=='0'&&el.days0=='0'">秒</span>
</p>

下面是js代码:

 setInterval(function() {
      vmi.tryGoodspRreviewList.forEach(function(val, index) {
          val.startleft--;
          var gettime = vmi.daojishiHandle(val.startleft);
          val.days0 = gettime.days0
          val.days = gettime.days
          val.hours1 = gettime.hours1;
          val.hours2 = gettime.hours2;
          val.minutes1 = gettime.minutes1;
          val.minutes2 = gettime.minutes2;
          val.seconds1 = gettime.seconds1;
          val.seconds2 = gettime.seconds2;
         })
 }, 1000)

 daojishiHandle:function(val) {
        var allday = parseInt(val / 24 / 60 / 60)

        var time = val % (24 * 3600)
        var hour = parseInt(time / 60 / 60);
        var minutes = parseInt(time / 60 - hour * 60);
        var seconds = time - hour * 60 * 60 - minutes * 60;

        var day2 = parseInt(allday / 10)
        var day1 = allday % 10

        var hour0 = parseInt(hour / 10);
        var hour1 = hour % 10;

        var minute0 = parseInt(minutes / 10);
        var minute1 = minutes % 10;

        var second0 = parseInt(seconds / 10);
        var second1 = seconds % 10;

        return { days0: day2, days: day1, hours1: hour0, hours2: hour1, minutes1: minute0, minutes2: minute1, seconds1: second0, seconds2: second1 }
    },

这个倒计时花了很多时间,请笑纳,如果有更好的,更简单的正确代码,欢迎分享~~~~