• The Preliminary Contest for ICPC Asia Nanjing 2019 C. Tsy's number 5


    https://nanti.jisuanke.com/t/41300
    题意:求(sum_{i=1}^nphi(i)phi(j)2^{phi(i)phi(j)})
    (f_i=sum_{k=1}^n[phi(k)==i])
    (sum_{i=1}^nphi(i)phi(j)2^{phi(i)phi(j)})
    (=sum_{i=1}^nsum_{j=1}^nf_if_jij2^{ij})
    (=2sum_{i=1}^nsum_{j=1}^if_if_jij2^{ij}-sum_{i=1}^nf_ii2^{i^2})
    (=2sum_{i=1}^nif_isum_{j=1}^ijf_j2^{i^2+j^2-(i-j)^2}-sum_{i=1}^nf_ii2^{i^2})
    (=2sum_{i=1}^nif_i{sqrt 2}^{i^2}sum_{j=1}^ijf_j{sqrt 2}^{j^2}{sqrt 2}^{-(i-j)^2}-sum_{i=1}^nf_ii2^{i^2})
    后一个(sum)ntt,预处理f,(sqrt2)的二次剩余

    //#pragma GCC optimize(2)
    //#pragma GCC optimize(3)
    //#pragma GCC optimize(4)
    //#pragma GCC optimize("unroll-loops")
    //#pragma comment(linker, "/stack:200000000")
    //#pragma GCC optimize("Ofast,no-stack-protector")
    //#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
    #include<bits/stdc++.h>
    //#include <bits/extc++.h>
    #define fi first
    #define se second
    #define db double
    #define mp make_pair
    #define pb push_back
    #define mt make_tuple
    #define pi acos(-1.0)
    #define ll long long
    #define vi vector<int>
    #define mod 998244353
    #define ld long double
    //#define C 0.5772156649
    #define ls l,m,rt<<1
    #define rs m+1,r,rt<<1|1
    #define pll pair<ll,ll>
    #define pil pair<int,ll>
    #define pli pair<ll,int>
    #define pii pair<int,int>
    #define ull unsigned long long
    #define bpc __builtin_popcount
    #define base 1000000000000000000ll
    #define fin freopen("1.in","r",stdin)
    #define fout freopen("a.txt","w",stdout)
    #define fio ios::sync_with_stdio(false);cin.tie(0)
    #define mr mt19937 rng(chrono::steady_clock::now().time_since_epoch().count())
    inline ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
    inline void sub(ll &a,ll b){a-=b;if(a<0)a+=mod;}
    inline void add(ll &a,ll b){a+=b;if(a>=mod)a-=mod;}
    template<typename T>inline T const& MAX(T const &a,T const &b){return a>b?a:b;}
    template<typename T>inline T const& MIN(T const &a,T const &b){return a<b?a:b;}
    inline ll mul(ll a,ll b,ll c){return (a*b-(ll)((ld)a*b/c)*c+c)%c;}
    inline ll qp(ll a,ll b){ll ans=1;while(b){if(b&1)ans=ans*a%mod;a=a*a%mod,b>>=1;}return ans;}
    inline ll qp(ll a,ll b,ll c){ll ans=1;while(b){if(b&1)ans=mul(ans,a,c);a=mul(a,a,c),b>>=1;}return ans;}
    
    using namespace std;
    //using namespace __gnu_pbds;
    
    const ull ba=233;
    const db eps=1e-5;
    const ll INF=0x3f3f3f3f3f3f3f3f;
    const int N=100000+10,maxn=2000000+10,inf=0x3f3f3f3f;
    
    int prime[N],cnt,phi[N],f[N];
    bool mark[N];
    void init()
    {
        phi[1]=1;
        for(int i=2;i<N;i++)
        {
            if(!mark[i])prime[++cnt]=i,phi[i]=i-1;
            for(int j=1;j<=cnt&&i*prime[j]<N;j++)
            {
                mark[i*prime[j]]=1;
                if(i%prime[j]==0)
                {
                    phi[i*prime[j]]=phi[i]*prime[j];
                    break;
                }
                phi[i*prime[j]]=phi[i]*phi[prime[j]];
            }
        }
    }
    ll x[N<<3],y[N<<3];
    int rev[N<<3];
    void getrev(int bit)
    {
        for(int i=0;i<(1<<bit);i++)
            rev[i]=(rev[i>>1]>>1) | ((i&1)<<(bit-1));
    }
    void ntt(ll *a,int n,int dft)
    {
        for(int i=0;i<n;i++)
            if(i<rev[i])
                swap(a[i],a[rev[i]]);
        for(int step=1;step<n;step<<=1)
        {
            ll wn=qp(3,(mod-1)/(step*2));
            if(dft==-1)wn=qp(wn,mod-2);
            for(int j=0;j<n;j+=step<<1)
            {
                ll wnk=1;
                for(int k=j;k<j+step;k++)
                {
                    ll x=a[k];
                    ll y=wnk*a[k+step]%mod;
                    a[k]=(x+y)%mod;a[k+step]=(x-y+mod)%mod;
                    wnk=wnk*wn%mod;
                }
            }
        }
        if(dft==-1)
        {
            ll inv=qp(n,mod-2);
            for(int i=0;i<n;i++)a[i]=a[i]*inv%mod;
        }
    }
    int main()
    {
        ll ty=116195171ll;
        init();
        int T;scanf("%d",&T);
        while(T--)
        {
            int n;scanf("%d",&n);
            memset(f,0,sizeof f);
            for(int i=1;i<=n;i++)f[phi[i]]++;
            int sz=0,len;
            while((1<<sz)<=n)sz++;sz++;
            len=(1<<sz);
            getrev(sz);
            x[0]=0;y[0]=1;
            for(int i=1;i<=n;i++)
            {
                ll te=qp(ty,1ll*i*i);
                x[i]=1ll*i*f[i]%mod*te%mod;
                y[i]=qp(te,mod-2);
            }
            for(int i=n+1;i<len;i++)x[i]=y[i]=0;
            ntt(x,len,1);ntt(y,len,1);
            for(int i=0;i<len;i++)x[i]=x[i]*y[i]%mod;
            ntt(x,len,-1);
            ll ans=0;
            for(int i=1;i<=n;i++)
            {
                add(ans,2ll*i*f[i]%mod*qp(ty,1ll*i*i)%mod*x[i]%mod);
                sub(ans,1ll*f[i]*f[i]%mod*i%mod*i%mod*qp(2,1ll*i*i)%mod);
            }
            printf("%lld
    ",ans);
        }
        return 0;
    }
    /********************
    
    ********************/
    
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  • 原文地址:https://www.cnblogs.com/acjiumeng/p/11446407.html
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