• HDU 2222 Keywords Search


    二次联通门 : HDU 2222 Keywords Search

    /*
        HDU 2222 Keyword Search 
        
        重新规范一下AC自动机的写法。。 
    
    */
    #include <cstring>
    #include <cstdio>
    #include <queue>
    #include <cstdlib>
    #define Max 1000009
    
    void read (int &now)
    {
        now = 0;
        register char word = getchar ();
        while (word < '0' || word > '9')
            word = getchar ();
        while (word >= '0' && word <= '9')
        {
            now = now * 10 + word - '0';
            word = getchar ();
        }
    }
    
    
    struct Trie_Data
    {
        Trie_Data *child[26];
        
        Trie_Data *Fail;
        int Count;
        
        Trie_Data ()
        {
            for (int i = 0; i < 26; i ++)
                this->child[i] = NULL;
            
            Fail = NULL;
            Count = 0;
        }
    };
    
    Trie_Data *Root; 
    std :: queue <Trie_Data *>Queue;
    
    class AC_Type
    {
    
        public :
            
            void Insert (char *key)
            {
                Trie_Data *now = Root;
                
                Trie_Data *pos;
                int Id;
                int Len = strlen (key);
                for (int i = 0; i < Len; i ++)
                {
                    Id = key[i] - 'a';
                    if (now->child[Id] == NULL)
                        now->child[Id] = new Trie_Data;                    
                    now = now->child[Id];
                }
                now->Count ++;
            }
            
            void AC_Build ()
            {
                Queue.push (Root); 
                Trie_Data *now;
                Trie_Data *pos;
                while (!Queue.empty ())
                {
                    pos = NULL;
                    now = *&Queue.front ();
                    Queue.pop ();
                    for (int i = 0; i < 26; i ++)
                    {
                        if (now->child[i] == NULL)
                            continue;
                        if (now == Root)
                            now->child[i]->Fail = Root;
                        else
                        {
                            pos = now->Fail;
                            for (; pos; pos = pos->Fail)
                                if (pos->child[i] != NULL)
                                {
                                    now->child[i]->Fail = pos->child[i];
                                    break;
                                }
                            if (pos == NULL)
                                now->child[i]->Fail = Root;
                        }
                        Queue.push (now->child[i]); 
                    }  
                }
            }
            
            int Query (char *key)
            {
                int Answer = 0;
                int Len = strlen (key);
                
                int Id;
                Trie_Data *now = Root;
                for (int i = 0; i < Len; i ++)
                {
                    Id = key[i] - 'a';
                    while (now->child[Id] == NULL && now != Root)
                        now = now->Fail;
                    now = now->child[Id];
                    if (now == NULL)
                        now = Root;
                    Trie_Data *pos = now;
                    for (; pos != Root && pos->Count >= 0; pos = pos->Fail)
                    {
                        Answer += pos->Count;
                        pos->Count = -1;
                    }
                }
                return Answer;
            }
    };
    
    AC_Type Make;
    
    char line[Max];
    
    int main (int argc, char *argv[])
    {
        int T, N;
        for (read (T); T --; )
        {
            Root = new Trie_Data;
            for (read (N); N --; )
            {
                scanf ("%s", line);
                Make.Insert (line); 
            }
            Make.AC_Build (); 
            scanf ("%s", line);
            printf ("%d
    ", Make.Query (line)); 
        }
        return 0;
    } 
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  • 原文地址:https://www.cnblogs.com/ZlycerQan/p/6978841.html
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