Description
The Recaman's sequence is defined by a0 = 0 ; for m > 0, a m = a m−1 − m if the rsulting a m is positive and not already in the sequence, otherwise a m = am−1 + m.
The first few numbers in the Recaman's Sequence is 0, 1, 3, 6, 2, 7, 13, 20, 12, 21, 11, 22, 10, 23, 9 ...
Given k, your task is to calculate a k.
The first few numbers in the Recaman's Sequence is 0, 1, 3, 6, 2, 7, 13, 20, 12, 21, 11, 22, 10, 23, 9 ...
Given k, your task is to calculate a k.
Input
The input consists of several test cases. Each line of the input contains an integer k where 0 <= k <= 500000.
The last line contains an integer −1, which should not be processed.
The last line contains an integer −1, which should not be processed.
Output
For each k given in the input, print one line containing a k to the output.
Sample Input
7 10000 -1
Sample Output
20 18658
题意:找第k个Recaman's sequence数。
注意:没什么好注意的。
ac代码:
1 #include<stdio.h> 2 int d[600000],vis[9000000]; 3 int main() 4 { 5 int a,b,i,j,n; 6 d[0]=0; 7 for(i=0;i<500005;i++) 8 { 9 if(d[i-1]-i<0||vis[d[i-1]-i]==1) 10 d[i]=d[i-1]+i; 11 else if(!vis[d[i-1]-i]) 12 d[i]=d[i-1]-i; 13 vis[d[i]]=1; 14 } 15 while(scanf("%d",&n)) 16 { 17 if(n==-1) 18 break; 19 printf("%d ",d[n]); 20 } 21 }