CDZSC_2015寒假新人（1）——基础 H

Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?       
Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.       
Note: if year Y is a leap year, then the 1st leap year is year Y.       

              

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.        Each test case contains two positive integers Y and N(1<=N<=10000).       

              

Output

For each test case, you should output the Nth leap year from year Y.       

              

Sample Input

3

2005 25

1855 12

2004 10000

              

Sample Output

2108

1904

43236

Hint

We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.

 

思路：比较笨。。。一年一年的+上去，如果是闰年+1，直到=n，因为循环结束会多+1，所以要减去1

 

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
int main()
{
#ifdef CDZSC_OFFLINE
    freopen("in.txt","r",stdin);
#endif
    int year,t,n,sum;
    scanf("%d",&t);
    while(t--)
    {
        sum=0;
        scanf("%d%d",&year,&n);
        while(sum<n)
        {
            if((year%4==0&&year%100!=0)||(year%400==0))
            {
                sum++;
            }
            year++;
        }
        printf("%d
",year-1);
    }
    return 0;
}