数学图形(1.25)cassini曲线

通过这种曲线可以看到一种由8到0的过度

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#http://www.mathcurve.com/courbes2d/cassini/cassini.shtml
vertices = 1000

t = from (-PI) to (PI)
a = 10
b = rand2(0, 4*a)
e = b/a;

p = a*sqrt(cos(2*t) + sqrt(e^4 - sin(2*t)^2))

x = p*cos(t)
y = p*sin(t)

面:

vertices = D1:512 D2:100

u = from (-PI) to (PI) D1
v = from (0) to (4) D2
a = 10

p = a*sqrt(cos(2*u) + sqrt(v^4 - sin(2*u)^2))

x = p*cos(u)
y = p*sin(u)