• Destroying the bus stations HDU


    题意:

      就是求最小割点

    解析:

      正向一遍spfa 反向一遍spfa  然后遍历每一条边,对于当前边 如果dis1[u] + dis2[v] + 1 <= k 那么就把这条边加入到网络流图中,

      每个点拆点 边权为1

      跑最大流即可

    代码还是改的那一题。。。

      

    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <queue>
    #include <cmath>
    #include <vector>
    #define mem(a,b) memset(a,b,sizeof(a))
    using namespace std;
    const int maxn = 1e3 + 10, INF = 0xfffffff, maxm = 100010;
    typedef long long LL;
    int n,m, cnt, s, t, k;
    int head[maxn], d[maxn], vis[maxn], dis1[maxn], dis2[maxn], head1[maxn], cur[maxn];
    int from[maxm], to[maxm];
    int bz[55][55], way[55][55];
    
    struct edge
    {
        int u, v, c, next;
    }Edge[maxm << 1];
    
    void add_(int u, int v, int c)
    {
        Edge[cnt].u = u;
        Edge[cnt].v = v;
        Edge[cnt].c = c;
        Edge[cnt].next = head1[u];
        head1[u] = cnt++;
    }
    
    void add_edge(int u, int v, int c)
    {
        add_(u, v, c);
        add_(v, u, 0);
    }
    
    bool bfs()
    {
        mem(d, 0);
        queue<int> Q;
        Q.push(s);
        d[s] = 1;
        while(!Q.empty())
        {
            int u = Q.front(); Q.pop();
            for(int i = head1[u]; i != -1; i = Edge[i].next)
            {
                edge e = Edge[i];
                if(!d[e.v] && e.c > 0)
                {
                    d[e.v] = d[u] + 1;
                    Q.push(e.v);
                    if(e.v == t) return 1;
                }
            }
        }
        return d[t] != 0;
    }
    
    int dfs(int u, int cap)
    {
        int ret = 0;
        if(u == t || cap == 0)
            return cap;
        for(int &i = cur[u]; i != -1; i = Edge[i].next)
        {
            edge e = Edge[i];
            if(d[e.v] == d[u] + 1 && e.c > 0)
            {
                int V = dfs(e.v, min(e.c, cap));
                Edge[i].c -= V;
                Edge[i ^ 1].c += V;
                ret += V;
                cap -= V;
                if(cap == 0) break;
            }
        }
        if(cap > 0) d[u] = -1;
        return ret;
    }
    
    int Dinic()
    {
        int ans = 0;
        while(bfs())
        {
            memcpy(cur, head1, sizeof(head1));
            ans += dfs(s, INF);
        }
        return ans;
    }
    
    struct node
    {
        int u, v, w, next;
    }Node[maxn * 10];
    
    void add(int u,int v,int w,int i)
    {
        Node[i].u = u;
        Node[i].v = v;
        Node[i].w = w;
        Node[i].next = head[u];
        head[u] = i;
    }
    void spfa(int s)
    {
        for(int i = 0; i < maxn; i++) d[i] = INF;
        queue<int> Q;
        d[s] = 0;
        mem(vis,0);
        Q.push(s);
        vis[s] = 1;
        while(!Q.empty())
        {
            int u = Q.front();Q.pop();
            vis[u] = 0;
            for(int i=head[u]; i!=-1; i=Node[i].next)
            {
                node e = Node[i];
                if(d[e.v] > d[u] + e.w)
                {
                    d[e.v] = d[u] + e.w;
                    if(!vis[e.v])
                    {
                        Q.push(e.v);
                        vis[e.v] = 1;
                    }
                }
            }
    
        }
    }
    
    int main()
    {
        int T,A,B;
        while(~scanf("%d%d%d", &n, &m, &k))
        {
            if(n==0&&m==0&&k==0)
            break;
            mem(way, 0);
            mem(bz, 0);
            mem(Node,0);
            mem(head,-1);
            mem(head1, -1);
            cnt = 0;
            for(int i=0; i<m; i++)
            {
                scanf("%d%d",&from[i],&to[i]);
                if(!bz[from[i]][to[i]])
                {
                    add(from[i],to[i],1,i), bz[from[i]][to[i]] = 1;
                    way[from[i]][to[i]] = 1;
                }
            }
            s = 1, t = n;
            spfa(s);
            mem(Node,0);
            for(int i=1; i<=n; i++)
                dis1[i] = d[i];
            mem(head,-1);
            for(int i=0; i<m; i++)
                add(to[i],from[i],1,i);
            spfa(t);
            for(int i=1; i<=n; i++)
                dis2[i] = d[i];
            mem(bz, 0);
            s = 1 + n, t = n;
            for(int i = 1; i <= n; i++)
            {
                for(int j = 1; j <= n; j++)
                {
                    if(way[i][j] && dis1[i] + dis2[j] + 1 <= k)
                        add_edge(i, j, INF);
                }
                add_edge(i, i + n, 1);
            }
    
            printf("%d
    ",Dinic());
        }
        return 0;
    }
    自己选择的路,跪着也要走完。朋友们,虽然这个世界日益浮躁起来,只要能够为了当时纯粹的梦想和感动坚持努力下去,不管其它人怎么样,我们也能够保持自己的本色走下去。
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  • 原文地址:https://www.cnblogs.com/WTSRUVF/p/9850863.html
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