• 每个字符串至少出现两次且不重叠的最长子串


    Relevant Phrases of Annihilation

     SPOJ - PHRASES

    https://cn.vjudge.net/problem/SPOJ-PHRASES

    呵。。。呵。。。

    我觉得我写的很对呀。。。

    真是的。。。

    这么漂亮。。。

    行吧。。一下午没检查出来哪里有问题 真是的  太过分了。。。emm。。。

    过几天再看。。啊啊啊。。。

    网上正确代码:

    #include <iostream>
    #include <cstdio>
    #include <sstream>
    #include <cstring>
    #include <map>
    #include <cctype>
    #include <set>
    #include <vector>
    #include <stack>
    #include <queue>
    #include <algorithm>
    #include <cmath>
    #define rap(i, a, n) for(int i=a; i<=n; i++)
    #define rep(i, a, n) for(int i=a; i<n; i++)
    #define lap(i, a, n) for(int i=n; i>=a; i--)
    #define lep(i, a, n) for(int i=n; i>a; i--)
    #define rd(a) scanf("%d", &a)
    #define rlld(a) scanf("%lld", &a)
    #define rc(a) scanf("%c", &a)
    #define rs(a) scanf("%s", a)
    #define MOD 2018
    #define LL long long
    #define ULL unsigned long long
    #define Pair pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define _  ios_base::sync_with_stdio(0),cin.tie(0)
    //freopen("1.txt", "r", stdin);
    using namespace std;
    const int maxn = 101000, INF = 0x7fffffff;
    int s[maxn];
    int sa[maxn], t[maxn], t2[maxn], c[maxn], n;
    int ran[maxn], height[maxn], length[105];
    void get_sa(int m)
    {
        int i, *x = t, *y = t2;
        for(i = 0; i < m; i++) c[i] = 0;
        for(i = 0; i < n; i++) c[x[i] = s[i]]++;
        for(i = 1; i < m; i++) c[i] += c[i-1];
        for(i = n-1; i >= 0; i--) sa[--c[x[i]]] = i;
        for(int k = 1; k <= n; k <<= 1)
        {
            int p = 0;
            for(i = n-k; i < n; i++) y[p++] = i;
            for(i = 0; i < n; i++) if(sa[i] >= k) y[p++] = sa[i] - k;
            for(i = 0; i < m; i++) c[i] = 0;
            for(i = 0; i < n; i++) c[x[y[i]]]++;
            for(i = 0; i< m; i++) c[i] += c[i-1];
            for(i = n-1; i >= 0; i--) sa[--c[x[y[i]]]] = y[i];
            swap(x, y);
            p = 1; x[sa[0]] = 0;
            for(i = 1; i < n; i++)
                x[sa[i]] = y[sa[i-1]] == y[sa[i]] && y[sa[i-1]+k] == y[sa[i]+k] ? p-1 : p++;
            if(p >= n) break;
            m = p;
        }
        int k = 0;
        for(i = 0; i < n; i++) ran[sa[i]] = i;
        for(i = 0; i < n; i++)
        {
            if(k) k--;
            int j = sa[ran[i]-1];
            while(s[i+k] == s[j+k]) k++;
            height[ran[i]] = k;
        }
    }
    char str[maxn];
    int id[maxn];
    struct node
    {
        int Min;
        int Max;
        int flag;
    } anspos[15];
    void ini()
    {
        for(int i = 0; i <= 12; i++)
            anspos[i].Min = 0x3f3f3f3f,anspos[i].Max = -1;
    }
    bool can(int len,int n,int num)
    {
        int l = 2,r = 2;
        ini();
        for(int i = 2; i <= n; i++)
        {
            if(height[i] >= len)
            {
                int id1=id[sa[i-1]];
                int id2=id[sa[i]];
    
                anspos[id1].Max=max(anspos[id1].Max,sa[i-1]);
                anspos[id1].Min=min(anspos[id1].Min,sa[i-1]);
    
                anspos[id2].Max=max(anspos[id2].Max,sa[i]);
                anspos[id2].Min=min(anspos[id2].Min,sa[i]);
                int t;
                for(t = 0; t < num; t++)
                    if(anspos[t].Max - anspos[t].Min < len)
                        break;
                if(t == num)
                    return 1;
            }
            else
            {
                for(int j = 0; j <= 10; j++)
                    anspos[j].Min = 0x3f3f3f3f,anspos[j].Max = -1;
            }
        }
        for(int i = 0; i < num; i++)
            if(!anspos[i].flag)
                return 0;
        return 1;
    }
    int main()
    {
        int k,q,t;
        scanf("%d",&t);
        while(t--)
        {
            ini();
            int tot = 0,len = 0x3f3f3f3f;
            scanf("%d",&q);
            for(int i = 0; i < q; i++)
            {
                scanf("%s",str);
                for(int j = 0; str[j]!=''; j++)
                {
                    id[tot] = i;
                    s[tot++] = str[j];
                }
                id[tot] = i;
                s[tot++] = '#'+i;
                len = min(len,(int)strlen(str));
            }
            s[tot] = 0;
            n = tot+1;
            get_sa(200);
    //        for(int i=1; i<n; i++)
    //            cout<< height[i] <<endl;
            int l = 0,r = len;
            int ans = 0;
            while(l <= r)
            {
                int mid = l + (r - l) / 2;
                if(can(mid,tot,q))
                {
                    l = mid+1;
                }
                else
                    r = mid-1;
            }
            printf("%d
    ",r);
        }
        return 0;
    }

    我的:

    #include <iostream>
    #include <cstdio>
    #include <sstream>
    #include <cstring>
    #include <map>
    #include <cctype>
    #include <set>
    #include <vector>
    #include <stack>
    #include <queue>
    #include <algorithm>
    #include <cmath>
    #define rap(i, a, n) for(int i=a; i<=n; i++)
    #define rep(i, a, n) for(int i=a; i<n; i++)
    #define lap(i, a, n) for(int i=n; i>=a; i--)
    #define lep(i, a, n) for(int i=n; i>a; i--)
    #define rd(a) scanf("%d", &a)
    #define rlld(a) scanf("%lld", &a)
    #define rc(a) scanf("%c", &a)
    #define rs(a) scanf("%s", a)
    #define MOD 2018
    #define LL long long
    #define ULL unsigned long long
    #define Pair pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define _  ios_base::sync_with_stdio(0),cin.tie(0)
    //freopen("1.txt", "r", stdin);
    using namespace std;
    const int maxn = 101000, INF = 0x7fffffff;
    int s[maxn];
    int sa[maxn], t[maxn], t2[maxn], c[maxn], n;
    int ran[maxn], height[maxn], length[105];
    void get_sa(int m)
    {
        int i, *x = t, *y = t2;
        for(i = 0; i < m; i++) c[i] = 0;
        for(i = 0; i < n; i++) c[x[i] = s[i]]++;
        for(i = 1; i < m; i++) c[i] += c[i-1];
        for(i = n-1; i >= 0; i--) sa[--c[x[i]]] = i;
        for(int k = 1; k <= n; k <<= 1)
        {
            int p = 0;
            for(i = n-k; i < n; i++) y[p++] = i;
            for(i = 0; i < n; i++) if(sa[i] >= k) y[p++] = sa[i] - k;
            for(i = 0; i < m; i++) c[i] = 0;
            for(i = 0; i < n; i++) c[x[y[i]]]++;
            for(i = 0; i< m; i++) c[i] += c[i-1];
            for(i = n-1; i >= 0; i--) sa[--c[x[y[i]]]] = y[i];
            swap(x, y);
            p = 1; x[sa[0]] = 0;
            for(i = 1; i < n; i++)
                x[sa[i]] = y[sa[i-1]] == y[sa[i]] && y[sa[i-1]+k] == y[sa[i]+k] ? p-1 : p++;
            if(p >= n) break;
            m = p;
        }
        int k = 0;
        for(i = 0; i < n; i++) ran[sa[i]] = i;
        for(i = 0; i < n; i++)
        {
            if(k) k--;
            int j = sa[ran[i]-1];
            while(s[i+k] == s[j+k]) k++;
            height[ran[i]] = k;
        }
    }
    
    struct node
    {
        int minn, maxx;
    }Node[15];
    
    int solve(int k, int q)
    {
        for(int i=1; i<=q; i++)
            Node[i].minn = INF, Node[i].maxx = -INF;
        int cnt = 0;
        for(int i=1; i<n; i++)
        {
            if(height[i] < k)
            {
                for(int j=1; j<=q; j++)
                {
                    Node[j].minn = INF, Node[j].maxx = -INF;
                }
    
                continue;
            }
            for(int j=1; j<=q; j++)
            {
                if(sa[i] > length[j-1] && sa[i] < length[j])
                {
                    Node[j].minn = min(Node[j].minn, sa[i]);
                    Node[j].maxx = max(Node[j].maxx, sa[i]);
                }
                if(sa[i-1] > length[j-1] && sa[i-1] < length[j])
                {
                    Node[j].minn = min(Node[j].minn, sa[i-1]);
                    Node[j].maxx = max(Node[j].maxx, sa[i-1]);
                }
            }
            cnt = 0;
            for(int j=1; j<=q; j++)
            {
                if(Node[j].maxx - Node[j].minn >= k)
                    cnt++;
            }
            if(cnt == q) return true;
    
        }
        return false;
    }
    
    int T, q, len;
    char str[maxn];
    int main()
    {
        rd(T);
        while(T--)
        {
            n = 0;
            int l = 0, r = INF;
            length[0] = 0;
            rd(q);
    
            rep(i, 0, q)
            {
                rs(str);
                len = strlen(str);
                r = min(r, len);
                rep(j, 0, len)
                    s[n++] = str[j];
                length[i+1] = n;
                s[n++] = '#' + i;
            }
            s[n++] = 0;
            get_sa(200);
    //        for(int i=1; i<n; i++)
    //            cout<< height[i] <<endl;
        //    cout<< l << "  " << r <<endl;
            while(l <= r)
            {
                int mid = l + (r - l) / 2;
                if(solve(mid, q)) l = mid + 1;
                else r = mid - 1;
            //    cout<< 111 <<endl;
            }
            cout<< r <<endl;
    
        }
    
    
    
    
    
        return 0;
    }
    自己选择的路,跪着也要走完。朋友们,虽然这个世界日益浮躁起来,只要能够为了当时纯粹的梦想和感动坚持努力下去,不管其它人怎么样,我们也能够保持自己的本色走下去。
  • 相关阅读:
    A
    B
    C
    I
    公共最大字串长度
    docker run 的背后的故事(zz)
    python之多并发socket(zz)
    Python垃圾回收机制:gc模块(zz)
    我要做的git的分享(zz)
    SpringMVC框架入门配置 IDEA下搭建Maven项目(zz)
  • 原文地址:https://www.cnblogs.com/WTSRUVF/p/9498076.html
Copyright © 2020-2023  润新知