• leetcode[98]Validate Binary Search Tree


    Given a binary tree, determine if it is a valid binary search tree (BST).

    Assume a BST is defined as follows:

    • The left subtree of a node contains only nodes with keys less than the node's key.
    • The right subtree of a node contains only nodes with keys greater than the node's key.
    • Both the left and right subtrees must also be binary search trees.

    confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.

    /**
     * Definition for binary tree
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    class Solution {
    public:
    /*
    类型名称             字节数         取值范围
    signed char            1           -128~+127
    short int              2           -32768~+32767
    int                    4        -2147438648~+2147438647
    long int               4        -2147438648~+2141438647
    long long int          8     -9223372036854775808~+9223372036854775807
    */
    bool check(TreeNode *node, long long leftmin, long long rightmax)
    {
        if(node==NULL)return true;
        return (node->val>leftmin&&node->val<rightmax)&&check(node->left,leftmin,node->val)&&check(node->right,node->val,rightmax);
    }
        bool isValidBST(TreeNode *root) {
            return check(root,-9223372036854775808,9223372036854775807);
        }
    };
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  • 原文地址:https://www.cnblogs.com/Vae1990Silence/p/4281370.html
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