• BZOJ 1137 半平面交


    半平面交的板子

    //By SiriusRen
    #include <bits/stdc++.h>
    #define double long double
    using namespace std;
    const int N=100050;
    const double eps=1e-10;
    int n,m,xx,yy,tot;
    double Ans;
    vector<int>vec[N];
    struct Point{double x,y;}point[N];
    struct Line{Point a,b;double angle;}line[N],q[N];
    void addline(Line &l,Point a,Point b){
        l.a=a,l.b=b,l.angle=atan2(b.y-a.y,b.x-a.x);
    }
    Point operator-(Point a,Point b){
        Point c;c.x=a.x-b.x,c.y=a.y-b.y;return c;
    }
    double operator*(Point a,Point b){
        return a.x*b.y-a.y*b.x;
    }
    bool operator<(Line a,Line b){
        if(a.angle==b.angle)return (b.b-a.a)*(b.a-a.a)>0;
        return a.angle<b.angle;
    }
    Point inter(Line a,Line b){
        double k1,k2,t;
        k1=(a.b-b.a)*(b.b-b.a);
        k2=(b.b-b.a)*(a.a-b.a);
        t=k1/(k1+k2);
        Point ans;
        ans.x=a.b.x+(a.a.x-a.b.x)*t;
        ans.y=a.b.y+(a.a.y-a.b.y)*t;
        return ans;
    }
    double dis(Point x,Point y){
        x=y-x;
        return sqrt(x.x*x.x+x.y*x.y);
    }
    bool judge(Line a,Line b,Line t){
        Point p=inter(a,b);
        return (t.a-p)*(t.b-p)<0;
    }
    void bpmj(){
        sort(line+1,line+1+tot);
        n=0;
        for(int i=1;i<=tot;i++){
            if(abs(line[i].angle-line[i-1].angle)>eps)n++;
            line[n]=line[i];
        }
        int r=1,l=0;
        q[0]=line[1],q[1]=line[2];
        for(int i=3;i<=n;i++){
            while(l<r&&judge(q[r],q[r-1],line[i]))r--;
            while(l<r&&judge(q[l],q[l+1],line[i]))l++;
            q[++r]=line[i];
        }
        while(l<r&&judge(q[r],q[r-1],q[l]))r--;
        while(l<r&&judge(q[l],q[l+1],q[r]))l++;
        q[r+1]=q[l],tot=0;
        for(int i=l;i<=r;i++)point[++tot]=inter(q[i],q[i+1]);
        point[++tot]=point[1];
        for(int i=1;i<tot;i++)Ans+=dis(point[i],point[i+1]);
    }
    int main(){
        scanf("%d%d",&n,&m);
        for(int i=1;i<=n;i++)
            scanf("%Lf%Lf",&point[i].x,&point[i].y);
        Ans=-dis(point[1],point[n]);
        for(int i=1;i<=m;i++){
            scanf("%d%d",&xx,&yy);
            if(xx>yy)swap(xx,yy);
            vec[xx].push_back(yy);
        }
        for(int i=1,j,k;i<=n;i++){
            sort(vec[i].begin(),vec[i].end());
            for(j=n,k=vec[i].size()-1;j>i&&~k;j--,k--)
                if(vec[i][k]!=j)break;
            if(i==1&&j==n){printf("%.10Lf
    ",dis(point[1],point[n]));return 0;}
            if(j>i)addline(line[++tot],point[j],point[i]);
        }addline(line[++tot],point[1],point[n]);
        bpmj();
        printf("%.10Lf
    ",Ans);
    }
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  • 原文地址:https://www.cnblogs.com/SiriusRen/p/6898975.html
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