• POJ 2104 可持久化线段树


    这就是以后我的可持久化线段树的模板啦~

    //By SiriusRen
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    #define N 100010
    int n,m,cnt,b[N],cpy[N],now,root[N];
    struct Tree{int l,r,cnt;}tree[N*20];
    void push_up(int pos){tree[pos].cnt=tree[tree[pos].l].cnt+tree[tree[pos].r].cnt;}
    int build(int l,int r){
        int pos=now++;
        if(l==r)return pos;
        int mid=(l+r)>>1;
        tree[pos].l=build(l,mid);
        tree[pos].r=build(mid+1,r);
        push_up(pos);
        return pos;
    }
    int insert(int o,int l,int r,int arr){
        int pos=now++;
        tree[pos]=tree[o];
        if(l==arr&&r==arr){tree[pos].cnt++;return pos;}
        int mid=(l+r)>>1;
        if(arr<=mid)tree[pos].l=insert(tree[o].l,l,mid,arr);
        else tree[pos].r=insert(tree[o].r,mid+1,r,arr);
        push_up(pos);
        return pos;
    }
    int query(int l,int r,int o,int v,int kth){
        if(l==r)return l;
        int mid=(l+r)>>1,res=tree[tree[v].l].cnt-tree[tree[o].l].cnt;
        if(kth<=res)return query(l,mid,tree[o].l,tree[v].l,kth);
        else return query(mid+1,r,tree[o].r,tree[v].r,kth-res);
    }
    int main(){
        scanf("%d%d",&n,&m);
        for(int i=1;i<=n;i++)scanf("%d",&b[i]),cpy[i]=b[i];
        sort(cpy+1,cpy+1+n);cnt=unique(cpy+1,cpy+1+n)-cpy-1;
        root[0]=build(1,cnt);
        for(int i=1;i<=n;i++)
            root[i]=insert(root[i-1],1,cnt,lower_bound(cpy+1,cpy+1+cnt,b[i])-cpy);
        while(m--){
            int xx,yy,zz;scanf("%d%d%d",&xx,&yy,&zz);
            printf("%d
    ",cpy[query(1,cnt,root[xx-1],root[yy],zz)]);
        }
    }

    这里写图片描述

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  • 原文地址:https://www.cnblogs.com/SiriusRen/p/6532266.html
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