Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
本题依次寻找左右两端的高度围成的最多的水,然后移动最矮的一边高度。时间:38ms。我的代码:
class Solution { public: int maxArea(vector<int> &height) { int capability = 0; size_t left = 0, right = height.size() - 1; while (left < right){ const int water = min(height[left], height[right]) * (right - left); if (water > capability) capability = water; if (height[left] < height[right]) ++left; else --right; } return capability; } };