• Black and white painting 一道很简单的规律题目


    View Code
    Black and white painting
    
    Time Limit: 1000MS Memory limit: 65536K
    
    题目描述
    
    You are visiting the Centre Pompidou which contains a lot of modern paintings. In particular you notice one painting which consists solely of black and white squares, arranged in rows and columns like in a chess board (no two adjacent squares have the same colour). By the way, the artist did not use the tool of problem A to create the painting.
    
    Since you are bored, you wonder how many 8 × 8 chess boards are embedded within this painting. The bottom right corner of a chess board must always be white.
    
    输入
    
    The input contains several test cases. Each test case consists of one line with three integers n, m and c. (8 ≤ n, m ≤ 40000), where n is the number of rows of the painting, and m is the number of columns of the painting. c is always 0 or 1, where 0 indicates that the bottom right corner of the painting is black, and 1 indicates that this corner is white.
    
    The last test case is followed by a line containing three zeros.
    
    输出
    
    For each test case, print the number of chess boards embedded within the given painting.
    
    其实这道题目只需要把他所描述的那张图,空出上面的七行,和左面的七列,让后看剩下的有多少个白色的格子就行了,但是对于右下角给定的颜色不同或许会有一点点不同~~具体怎么操作就看代码了~~
    
    #include<stdio.h>
    void main()
    {
    int m,n,t;
    while(scanf("%d%d%d",&m,&n,&t)&&(m||t||n))
    {
    if(m<8 || n<8)
    printf("0\n");
    else
    {
    //此处为去掉前(七行七列)的操作
    m -= 7;
    n -= 7;
    //如果右下角是白色的就把剩下的行列数乘积+1
    if(t)
    printf("%d\n",(m*n+1)/2);
    else
    printf("%d\n",m*n/2);
    }
    }
    }
    
    只供参考,禁止copy
     
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  • 原文地址:https://www.cnblogs.com/SDUTYST/p/2404334.html
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