Given n, generate all structurally unique BST's (binary search trees) that store values 1...n.
For example,
Given n = 3, your program should return all 5 unique BST's shown below.
1 3 3 2 1 / / / 3 2 1 1 3 2 / / 2 1 2 3
confused what "{1,#,2,3}"
means? > read more on how binary tree is serialized on OJ.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<TreeNode *> generate(int beg, int end) { vector<TreeNode* > ret; if (beg > end) { ret.push_back(NULL); return ret; } for(int i = beg; i <= end; i++) { vector<TreeNode* > leftTree = generate(beg, i - 1); vector<TreeNode* > rightTree = generate(i + 1, end); for(int j = 0; j < leftTree.size(); j++) for(int k = 0; k < rightTree.size(); k++) { TreeNode *node = new TreeNode(i + 1); ret.push_back(node); node->left = leftTree[j]; node->right = rightTree[k]; } } return ret; } vector<TreeNode *> generateTrees(int n) { // Start typing your C/C++ solution below // DO NOT write int main() function return generate(0, n - 1); } };