1 #include <iostream> 2 #include <string> 3 #include <vector> 4 #include <fstream> 5 #include <sstream> 6 7 using namespace std; 8 9 string int2str(int number) 10 { 11 string strNumber; 12 int result = abs(number); 13 14 if (result == 0) 15 { 16 strNumber = "0"; 17 } 18 else 19 { 20 while (result) 21 { 22 strNumber = (char)(result % 10 + '0' ) + strNumber; 23 result /= 10; 24 } 25 } 26 27 if (number < 0) 28 strNumber = "-" + strNumber; 29 30 return strNumber; 31 } 32 33 int main(int argc, char *argv[]) 34 { 35 string strNumber = int2str(-797); 36 cout << strNumber << endl; 37 38 return 0; 39 }
这里是将int转化为string类型，思路是将int型数据除以10得到从而得到每一位。
1 #include <iostream> 2 #include <string> 3 #include <vector> 4 #include <fstream> 5 #include <sstream> 6 7 using namespace std; 8 9 int str2int(const string& strNumber) 10 { 11 if (strNumber.length() == 0) 12 { 13 cout << "Input error!" << endl; 14 return -1; 15 } 16 17 string tmpStr(strNumber); 18 if (tmpStr[0] == '-') 19 tmpStr.assign(tmpStr.begin() + 1, tmpStr.end()); 20 21 int number = 0; 22 for (size_t i = 0; i < tmpStr.length(); i++) 23 { 24 number = number * 10 + (tmpStr[i] - '0'); 25 } 26 27 if (strNumber[0] == '-') 28 number *= -1; 29 30 return number; 31 } 32 33 int main(int argc, char *argv[]) 34 { 35 int number = str2int(string("-70865")); 36 cout << number << endl; 37 38 return 0; 39 }
将string转化为int类型。