• Rain on your Parade HDU


    //HK算法模板题 
    #include <bits/stdc++.h>
    #define inf 0x3f3f3f3f
    const int  maxn=3030;
    using namespace std;
    int e[maxn*maxn],ne[maxn*maxn],h[maxn*maxn],idx;
    struct node {
    	double x,y,v;
    } a[maxn];
    
    int lx[maxn],ly[maxn],dx[maxn],dy[maxn];
    bool vis[maxn];
    int T,n,m,t,dis;
    void init() {
    	memset(lx,-1,sizeof(lx));
    	memset(ly,-1,sizeof(ly));
    	memset(h,-1,sizeof(h));
    	idx = 0;
    }
    void add(int a,int b) {
    	e[idx]=b;
    	ne[idx]=h[a];
    	h[a]=idx++;
    }
    double dist(double x, double y, double xx, double yy) {
    	return sqrt((x - xx) * (x - xx) + (y - yy) * (y - yy));
    }
    bool Search() {
    	queue<int> q;
    	dis = inf;
    	memset(dx,-1,sizeof(dx));
    	memset(dy,-1,sizeof(dy));
    	for(int i=0; i<n; i++) {
    		if(lx[i] == -1) {
    			q.push(i);
    			dx[i] = 0;
    		}
    	}
    	while(!q.empty()) {
    		int u = q.front();
    		q.pop();
    		if(dx[u] > dis) 
    			break;
    		for(int i=h[u]; i!=-1; i=ne[i]) {
    			int v = e[i];
    			if(dy[v] == -1) {
    				dy[v] = dx[u] + 1;
    				if(ly[v] == -1) 
    					dis = dy[v];
    				else {
    					dx[ly[v]] = dy[v] + 1;
    					q.push(ly[v]);
    				}
    			}
    		}
    	}
    	return dis != inf;
    }
    bool dfs(int u) {
    	for(int i=h[u]; i!=-1; i=ne[i]) {
    		int v = e[i];
    		if(!vis[v] && dy[v] == dx[u] + 1) {
    			vis[v] = true;
    			if(ly[v] != -1 && dy[v] == dis) continue;
    			if(ly[v] == -1 || dfs(ly[v])) {
    				ly[v] = u;
    				lx[u] = v;
    				return true;
    			}
    		}
    	}
    	return false;
    }
    
    int Hopcroft_Karp() {
    	int sum = 0;
    	while( Search() ) {
    		memset(vis,false,sizeof(vis));
    		for(int i=0; i<n; i++) {
    			if(lx[i] == -1 && dfs(i)) 
    				sum ++;
    		}
    	}
    	return sum;
    }
    int main() {
    	int Case = 1;
    	scanf("%d",&T);
    	while(T--) {
    		init();
    		scanf("%d%d",&t,&n);
    		for(int i=0; i<n; i++) 
    			scanf("%lf%lf%lf",&a[i].x,&a[i].y,&a[i].v);
    		scanf("%d",&m);
    		for(int i=0; i<m; i++) 
    		{
    			double xx, yy;
    			scanf("%lf%lf",&xx,&yy);
    			for(int j=0; j<n; j++) {
    				double zz = dist(xx, yy, a[j].x, a[j].y);
    				if(a[j].v * t >= zz) 
    					add(j ,i);
    			}
    		}
    		int ans = Hopcroft_Karp();
    		printf("Scenario #%d:
    %d
    
    ",Case ++, ans);
    	}
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/QingyuYYYYY/p/12422833.html
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