Given a string s, partition s such that every substring of the partition is a palindrome.
Return all possible palindrome partitioning of s.
For example, given s = "aab"
,
Return
[ ["aa","b"], ["a","a","b"] ]
Solution:
1 public class Solution { 2 public List<List<String>> partition(String s) { 3 List<List<String>> result=new ArrayList<List<String>>(); 4 List<String> temp=new ArrayList<String>(); 5 dfs(result,temp,s); 6 return result; 7 } 8 9 private void dfs(List<List<String>> result, List<String> temp, String s) { 10 // TODO Auto-generated method stub 11 if(s.length()==0){ 12 result.add(new ArrayList<String>(temp)); 13 return; 14 } 15 for(int i=1;i<=s.length();++i){ 16 String str=s.substring(0, i); 17 if(isPalindrome(str)){ 18 temp.add(str); 19 dfs(result, temp, s.substring(i)); 20 temp.remove(temp.size()-1); 21 } 22 } 23 } 24 25 private boolean isPalindrome(String str) { 26 // TODO Auto-generated method stub 27 int end=str.length()-1; 28 int start=0; 29 while(start<end){ 30 if(str.charAt(start)!=str.charAt(end)) 31 return false; 32 start++; 33 end--; 34 } 35 return true; 36 } 37 }