• HDU 4965 Fast Matrix Calculation 矩阵乘法 乘法结合律


    一种奇葩的写法,纪念一下当时的RE。

      1 #include <iostream>
      2 #include <cstdio>
      3 #include <cstring>
      4 #include <cstdlib>
      5 #include <cmath>
      6 #include <algorithm>
      7 #include <string>
      8 #include <queue>
      9 #include <stack>
     10 #include <vector>
     11 #include <map>
     12 #include <set>
     13 #include <functional>
     14 #include <cctype>
     15 #include <time.h>
     16 
     17 using namespace std;
     18 
     19 const int INF = 1<<30;
     20 const int MAXN = 1005;
     21 
     22 struct Matrix {
     23     int a[MAXN][MAXN];
     24     int col, row;
     25 };
     26 
     27 Matrix tMu;
     28 
     29 void multiplication(const Matrix &x, const Matrix &y) {
     30     tMu.row= x.row; tMu.col = y.col;
     31     for (int i = 0; i < tMu.row; i++)
     32         for (int j = 0; j < tMu.row; j++) {
     33             tMu.a[i][j] = 0;
     34             for (int k = 0; k < x.col; k++)
     35                 tMu.a[i][j] = (tMu.a[i][j]+x.a[i][k]*y.a[k][j])%6;
     36         }
     37 }
     38 
     39 Matrix a, b, ONE;
     40 Matrix t;
     41 Matrix tmp, res;
     42 
     43 int n, k;
     44 
     45 void pow(const Matrix &x, int d) {
     46     res = ONE; res.col = res.row = x.col;
     47     tmp = x;
     48     while (d>0) {
     49         if (d&1) {
     50             multiplication(res, tmp);
     51             res = tMu;
     52         }
     53         multiplication(tmp, tmp);
     54         tmp = tMu;
     55         d >>= 1;
     56     }
     57 }
     58 
     59 void solve() {
     60     multiplication(b, a);
     61     t = tMu;
     62     pow(t, n*n-1);
     63     t = res;
     64     multiplication(a, t);
     65     t = tMu;
     66     multiplication(t, b);
     67     t = tMu;
     68     int ans = 0;
     69     for (int i = 0; i < n; i++) {
     70         for (int j = 0; j < n; j++)
     71             ans += t.a[i][j];
     72     }
     73     printf("%d
    ", ans);
     74 }
     75 
     76 int main() {
     77     #ifdef Phantom01
     78         freopen("HDU4965.txt", "r", stdin);
     79     #endif //Phantom01
     80 
     81     for (int i = 0; i < MAXN; i++) {
     82         for (int j = 0; j < MAXN; j++)
     83             ONE.a[i][j] = 0;
     84         ONE.a[i][i] = 1;
     85     }
     86 
     87     while (scanf("%d%d", &n, &k)!=EOF && !(n==0&&k==0)) {
     88         a.row = b.col = n;
     89         a.col = b.row = k;
     90         for (int i = 0; i < n; i++)
     91             for (int j = 0; j < k; j++)
     92                 scanf("%d", &a.a[i][j]);
     93         for (int i = 0; i < k; i++)
     94             for (int j = 0; j < n; j++)
     95                 scanf("%d", &b.a[i][j]);
     96         solve();
     97     }
     98 
     99     return 0;
    100 }
    View Code
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  • 原文地址:https://www.cnblogs.com/Phantom01/p/4085343.html
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