• FWT


    前言

    没有前言

    讲解

    暂时不打算讲解

    放一个巨佬的博客供膜拜

    再来一个外校的巨佬

    练习

    板题(洛谷)

    代码

    板题代码

    //12252024832524
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #define TT template<typename T>
    using namespace std; 
    
    typedef long long LL;
    const int MAXN = 1 << 17 | 5;
    const int MOD = 998244353;
    const int inv2 = 499122177;
    int n,N;
    int a[MAXN],b[MAXN],a1[MAXN],b1[MAXN];
    
    LL Read()
    {
    	LL x = 0,f = 1;char c = getchar();
    	while(c > '9' || c < '0'){if(c == '-')f = -1;c = getchar();}
    	while(c >= '0' && c <= '9'){x = (x*10) + (c^48);c = getchar();}
    	return x * f;
    }
    TT void Put1(T x)
    {
    	if(x > 9) Put1(x/10);
    	putchar(x%10^48);
    }
    TT void Put(T x,char c = -1)
    {
    	if(x < 0) putchar('-'),x = -x;
    	Put1(x);
    	if(c >= 0) putchar(c);
    }
    TT T Max(T x,T y){return x > y ? x : y;}
    TT T Min(T x,T y){return x < y ? x : y;}
    TT T Abs(T x){return x < 0 ? -x : x;}
    
    int qpow(int x,int y)
    {
    	int ret = 1;
    	while(y){if(y & 1) ret = 1ll * ret * x % MOD;x = 1ll * x * x % MOD;y >>= 1;}
    	return ret;
    }
    void Add(int &x){if(x >= MOD) x -= MOD;}
    void Del(int &x){if(x < 0) x += MOD;}
    void fwtor(int *a,int opt)
    {
    	for(int i = 1;i < N;i <<= 1)//块长
    		for(int p = i << 1,j = 0;j < N;j += p)//第几个块 
    			for(int k = 0;k < i;++ k)//块内第几个 
    				if(opt == 1) Add(a[i+j+k] += a[j+k]);
    				else Del(a[i+j+k] -= a[j+k]);
    }
    void fwtand(int *a,int opt)
    {
    	for(int i = 1;i < N;i <<= 1)//块长
    		for(int p = i << 1,j = 0;j < N;j += p)//第几个块 
    			for(int k = 0;k < i;++ k)//块内第几个 
    				if(opt == 1) Add(a[j+k] += a[i+j+k]);
    				else Del(a[j+k] -= a[i+j+k]);
    }
    void fwtxor(int *a,int opt)
    {
    	for(int i = 1;i < N;i <<= 1)//块长
    		for(int p = i << 1,j = 0;j < N;j += p)//第几个块 
    			for(int k = 0;k < i;++ k)//块内第几个 
    			{
    				int x = a[j+k],y = a[i+j+k];
    				if(opt == 1) Add(a[j+k] = x+y),Del(a[i+j+k] = x-y);
    				else a[j+k] = 1ll * (x + y) * inv2 % MOD,a[i+j+k] = 1ll * (x - y) * inv2 % MOD;
    			}
    }
    
    int main()
    {
    //	freopen(".in","r",stdin);
    //	freopen(".out","w",stdout);
    	n = Read(); N = 1 << n;
    	for(int i = 0;i < N;++ i) a[i] = Read();
    	for(int i = 0;i < N;++ i) b[i] = Read();
    	//or
    	for(int i = 0;i < N;++ i) a1[i] = a[i],b1[i] = b[i];
    	fwtor(a1,1);
    	fwtor(b1,1);
    	for(int i = 0;i < N;++ i) a1[i] = 1ll * a1[i] * b1[i] % MOD;
    	fwtor(a1,-1);
    	for(int i = 0;i < N;++ i) Del(a1[i]),Put(a1[i],i == N - 1 ? '
    ' : ' ');
    	//and
    	for(int i = 0;i < N;++ i) a1[i] = a[i],b1[i] = b[i];
    	fwtand(a1,1);
    	fwtand(b1,1);
    	for(int i = 0;i < N;++ i) a1[i] = 1ll * a1[i] * b1[i] % MOD;
    	fwtand(a1,-1);
    	for(int i = 0;i < N;++ i) Del(a1[i]),Put(a1[i],i == N - 1 ? '
    ' : ' ');
    	//xor
    	fwtxor(a,1);
    	fwtxor(b,1);
    	for(int i = 0;i < N;++ i) a[i] = 1ll * a[i] * b[i] % MOD;
    	fwtxor(a,-1);
    	for(int i = 0;i < N;++ i) Del(a[i]),Put(a[i],i == N - 1 ? '
    ' : ' ');
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/PPLPPL/p/14366028.html
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