题目略带一点贪心的思想,先跑三遍最短路(边权为一,BFS比SPFA高效)
一起跑总比分开跑高效,枚举两人在何点汇合,输出最小值。
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstdlib>
#include <cstring>
#include <queue>
using namespace std;
const int MAXN=40005;
int head[MAXN],nume,p,w,n,m,b,tot=0x7fffffff/3;
struct edge{
int to,nxt;
}e[MAXN*2];
int dis[MAXN][4],wei[4];
bool f[MAXN];
int read(){
int rv=0,fh=1;
char c=getchar();
while(c<'0'||c>'9'){
if(c=='-') fh=-1;
c=getchar();
}
while(c>='0'&&c<='9'){
rv=(rv<<1)+(rv<<3)+c-'0';
c=getchar();
}
return fh*rv;
}
void adde(int from,int to){
e[++nume].to=to;
e[nume].nxt=head[from];
head[from]=nume;
}
void spfa(int x){
memset(f,0,sizeof(f));
for(int i=1;i<=n;i++){
dis[i][x]=0x7fffffff/3;
}
queue<int> q;
if(x==3) {
dis[n][x]=0;
q.push(n);
f[n]=1;
}else {dis[x][x]=0;q.push(x);f[x]=1;}
while(!q.empty()){
int u=q.front();
q.pop();
f[u]=0;
for(int i=head[u];i;i=e[i].nxt){
int v=e[i].to;
if(dis[v][x]>dis[u][x]+wei[x]){
dis[v][x]=dis[u][x]+wei[x];
if(!f[v]){
q.push(v);
f[v]=1;
}
}
}
}
}
int main(){
freopen("in.txt","r",stdin);
b=read();w=read();p=read();n=read();m=read();
for(int i=1;i<=m;i++){
int u=read(),v=read();
adde(u,v);adde(v,u);
}
wei[1]=b;wei[2]=w;wei[3]=p;
spfa(1);spfa(2);spfa(3);
for(int i=1;i<=n;i++){
int sum=dis[i][1]+dis[i][2]+dis[i][3];
tot=min(sum,tot);
}
cout<<tot;
fclose(stdin);
return 0;
}