• [LeetCode] 453. Minimum Moves to Equal Array Elements


    Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.

    Example:

    Input:
    [1,2,3]
    
    Output:
    3
    
    Explanation:
    Only three moves are needed (remember each move increments two elements):
    
    [1,2,3]  =>  [2,3,3]  =>  [3,4,3]  =>  [4,4,4]

    题意:每次给数组中n-1个数字+1,问最少执行多少次可以使得全部数字都一样
    这题和462是一类型的,我又是一开始写的462比较复杂那个,
    这题逆向思维,n-1个数字+1,那么可以看作某个数字-1
    全部减到最小那个数字就行了
    class Solution {
        public int minMoves(int[] nums) {
            int min = Integer.MAX_VALUE;
            for (int i = 0; i < nums.length; i++) {
                min = Math.min(min, nums[i]);
            }
            int sum = 0;
            for (int i = 0; i < nums.length; i++) {
                sum += Math.abs(min - nums[i]);
            }
            return sum;
        }
    }
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  • 原文地址:https://www.cnblogs.com/Moriarty-cx/p/9769726.html
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