也是一道ST表的板子题,很裸的RMQ问题,只需要在查询区间时处理一下下就好啦~
1 #include <cstdio> 2 #include <algorithm> 3 using namespace std; 4 const int maxn = 1000000 + 10; 5 int st[maxn][21], a[maxn], ans[maxn]; 6 int n, m, i, j, left, right; 7 int main() 8 { 9 scanf("%d%d", &n, &m); 10 for(i = 1; i <= n; i++) 11 { 12 scanf("%d", &a[i]); 13 st[i][0] = a[i]; 14 } 15 16 for(j = 1; (1<<j) <= n; j++) 17 for(i = 1; i <= n-(1<<j)+1; i++) 18 st[i][j] = min(st[i][j-1],st[i+(1<<(j-1))][j-1]); 19 20 right = m; 21 for(i = 1; i <= n-m+1; i++) 22 { 23 j = 0; 24 left = i; 25 while((1<<(j+1)) <= (right-left+1)) j++; 26 ans[i] = min(st[left][j],st[right-(1<<j)+1][j]); 27 right++; 28 } 29 30 for(i = 1; i <= n-m+1; i++) 31 printf("%d ",ans[i]); 32 return 0; 33 }