JavaWeb 发送get请求
CreationTime--2018年6月20日15点27分
Author:Marydon
1.前提
通过HttpClient来实现
2.具体实现
客户端如何发送请求?
所需jar包:
commons-httpclient-3.0.jar
commons-codec-1.9.jar
commons-logging-1.1.1.jar
导入
import org.apache.commons.httpclient.HttpClient; import org.apache.commons.httpclient.HttpStatus; import org.apache.commons.httpclient.methods.GetMethod;
/** * 发送get请求 * @explain * 1.请求体:get传参没有请求体 * 2.数据格式:直接拼接到url后面,如:url?key1=value1&key2=value2&... * @param url 路径及参数 * @return 服务器返回数据 */ public static String sendGet(String url) { // 用于接收返回的结果 String resultData = ""; try { HttpClient httpClient = new HttpClient(); httpClient.getHttpConnectionManager().getParams().setConnectionTimeout(3000); // 设置连接超时 httpClient.getHttpConnectionManager().getParams().setSoTimeout(180000); // 设置读取数据超时 httpClient.getParams().setContentCharset("UTF-8"); GetMethod get = new GetMethod(url); int status = httpClient.executeMethod(get); // 状态码为:200 if (status == HttpStatus.SC_OK) { resultData = get.getResponseBodyAsString(); } else { throw new RuntimeException("接口连接失败!"); } } catch (Exception e) { e.printStackTrace(); throw new RuntimeException("接口连接失败!"); } return resultData; }
服务器端如何接收客户端传递的数据?
request.getParameter("key")
3.客户端调用测试
public static void main(String[] args) { String requestUrl = "http://localhost:8070/test/rz/server/rzxx/at_VaildToken.do?un_value=B022420184794C7C9D5096CC5F3AE7D2"; // 发送post请求并接收返回结果 String resultData = sendGet(requestUrl); System.out.println(resultData); }