题意:给一个有向图,然后个m颗石头放在图上的几个点上,每次只能移动一步,如果不能移动者败
思路:dfs打表sg函数,然后求异或和
代码:
#include<queue> #include<cstring> #include<set> #include<map> #include<stack> #include<cmath> #include<vector> #include<cstdio> #include<iostream> #include<algorithm> #define eps 1e-9 typedef long long ll; const int maxn = 1000 + 10; const int seed = 131; const ll MOD = 1e9 + 7; const int INF = 0x3f3f3f3f; using namespace std; vector<int> G[maxn]; int in[maxn], n; int s[maxn], sg[maxn]; void dfs(int u){ if(G[u].size() == 0){ sg[u] = 0; return; } for(int i = 0; i < G[u].size(); i++){ int v = G[u][i]; if(sg[v] == -1) dfs(v); } memset(s, 0, sizeof(s)); for(int i = 0; i < G[u].size(); i++){ int v = G[u][i]; s[sg[v]] = 1; } for(int i = 0; i < maxn; i++){ if(!s[i]){ sg[u] = i; return; } } } int main(){ while(~scanf("%d", &n)){ memset(in, 0, sizeof(in)); memset(sg, -1, sizeof(sg)); for(int i = 0; i <= n - 1; i++){ int x, to; G[i].clear(); scanf("%d", &x); while(x--){ scanf("%d", &to); G[i].push_back(to); in[to]++; } } for(int i = 0; i <= n - 1; i++){ if(!in[i]){ dfs(i); } } int m; while(scanf("%d", &m) && m){ int ans = 0, x; while(m--){ scanf("%d", &x); ans ^= sg[x]; } if(ans == 0) printf("LOSE "); else printf("WIN "); } } return 0; }