• Q2:Reverse Words in a String


    Clarification:

      • What constitutes a word?
        A sequence of non-space characters constitutes a word.
      • Could the input string contain leading or trailing spaces?
        Yes. However, your reversed string should not contain leading or trailing spaces.
      • How about multiple spaces between two words?
        Reduce them to a single space in the reversed string.

    MyAnswer 1 (Java):

     1 public class Solution {
     2     public String reverseWords(String s) {
     3         String result = "";
     4         int i = 0;
     5         int j = s.length();
     6         for(i = s.length()-1; i >= 0; i--)
     7         {
     8             if(s.charAt(i) == ' ')
     9             {
    10                 if(i == s.length()-1)
    11                 {
    12                     j = i;
    13                     //continue;
    14                 }
    15                 else if(i == 0)
    16                 {
    17                     //i++;
    18                     break;
    19                 }
    20                 else if(j == i+1)
    21                 {
    22                     j = i;
    23                     //continue;
    24                 }
    25                 else
    26                 {
    27                     result = result.concat(s.substring(i+1,j)+" ");
    28                     j = i;
    29                 }
    30             }
    31         }
    32         result = result.concat(s.substring(i+1,j));
    33         if(!result.isEmpty() && result.charAt(result.length()-1) == ' ')
    34             result = result.substring(0,result.length()-1);
    35         return result;
    36     }
    37 }

     使代码更加精简,改为:

    MyAnswer 2(Java):

     1 public class Solution {
     2     public String reverseWords(String s) {
     3         
     4         String result = "";
     5         int j = s.length();
     6         int i = j-1;
     7         
     8         for(; i >= 0; i--)
     9         {
    10             if(s.charAt(i) == ' ')
    11             {
    12                 if(i == 0)
    13                 {
    14                     break;
    15                 }
    16                 else if(i != s.length()-1 && j != i+1)
    17                 {
    18                     result = result.concat(s.substring(i+1,j)+" ");
    19                 }
    20                 j = i;
    21             }
    22         }
    23         
    24         result = result.concat(s.substring(i+1,j));
    25         
    26         int k = result.length();
    27         if(!result.isEmpty() && result.charAt(k-1) == ' ')
    28             result = result.substring(0,k-1);
    29         return result;
    30     }
    31 }

    MyAnswer3 (C++):

     1 class Solution {
     2 public:
     3     void reverseWords(string &s) {
     4         string result = "";
     5         int j = 0;
     6         int i;
     7         for(i = s.length()-1; i >= 0; i--)
     8         {
     9             if(s[i] == ' ')
    10             {
    11                 if(j == 0)
    12                     continue;
    13                 result = result + s.substr(i+1, j) + " ";
    14                 j = 0;
    15                 continue;
    16             }
    17             j++;
    18         }
    19         result = result + s.substr(i+1, j);
    20         s = (result[result.length()-1] == ' ')?result.substr(0,result.length()-1):result;
    21     }
    22 };
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  • 原文地址:https://www.cnblogs.com/ISeeIC/p/4124752.html
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