People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.
Input
Each input file contains one test case which occupies a line containing the three decimal color values.
Output
For each test case you should output the Mars RGB value in the following format: first output “#”, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a “0” to the left.
Sample Input
15 43 71
Sample Output
#123456
- 属于一道简单的进制转换题,需要掌握点技巧,黄色的话要注意。
#include<iostream>
using namespace std;
char radix[13] = { '0','1','2','3','4','5','6','7','8','9','A','B','C' };
int z[6] = { 0 };
int jinzhi(int n)
{
int num = 0;
while (n != 0)
{
z[num++] = n % 13;
n /= 13;
}
return num - 1;
}
int main()
{
int n1, n2, n3;
cin >> n1 >> n2 >> n3;
cout << "#";
int a=jinzhi(n1);
int i = 1 - a;
for (int j = i; j > 0; j--)
{
cout << "0";
}
while (a != -1)
{
cout << radix[z[a]];
a--;
}
a = jinzhi(n2);
i = 1 - a;
for (int j = i; j > 0; j--)
{
cout << "0";
}
while (a != -1)
{
cout << radix[z[a]];
a--;
}
a = jinzhi(n3);
i = 1 - a;
for (int j = i; j > 0; j--)
{
cout << "0";
}
while (a != -1)
{
cout << radix[z[a]];
a--;
}
}