• [BZOJ4399]魔法少女LJJ(线段树合并)


    请仔细阅读数据范围,c<=7.
    线段树合并裸题,对于乘积大小比较,使用log即可。

     1 #include<cmath>
     2 #include<cstdio>
     3 #include<cstring>
     4 #include<algorithm>
     5 #define lson ls[x],L,mid
     6 #define rson rs[x],mid+1,R
     7 #define rep(i,l,r) for (int i=(l); i<=(r); i++)
     8 using namespace std;
     9 
    10 const int N=400010,K=N*16,M=1000000000;
    11 int Q,op,n,x,y,k,nd,rt[N],fa[N],sz[K],ls[K],rs[K];
    12 double sm[K];
    13 
    14 int get(int x){ return (fa[x]==x) ? x : fa[x]=get(fa[x]); }
    15 
    16 void ins(int &x,int L,int R,int pos,int k){
    17     if (!x) x=++nd;
    18     if (L==R){ sz[x]+=k; sm[x]+=k*log(L); return; }
    19     int mid=(L+R)>>1;
    20     if (pos<=mid) ins(lson,pos,k); else ins(rson,pos,k);
    21     sz[x]=sz[ls[x]]+sz[rs[x]]; sm[x]=sm[ls[x]]+sm[rs[x]];
    22 }
    23 
    24 int mdf0(int &x,int L,int R,int k){
    25     if (!x) return 0;
    26     if (L==R){ if (k>L) { x=0; return 1; } else return 0; }
    27     int mid=(L+R)>>1,res=0;
    28     if (k>mid) res+=sz[ls[x]],ls[x]=0,res+=mdf0(rson,k);
    29         else res=mdf0(lson,k);
    30     sz[x]=sz[ls[x]]+sz[rs[x]]; sm[x]=sm[ls[x]]+sm[rs[x]];
    31     return res;
    32 }
    33 
    34 int mdf1(int &x,int L,int R,int k){
    35     if (!x) return 0;
    36     if (L==R){ if (k<L) { x=0; return 1; } else return 0; }
    37     int mid=(L+R)>>1,res=0;
    38     if (k<=mid) res+=sz[rs[x]],rs[x]=0,res+=mdf1(lson,k);
    39         else res=mdf1(rson,k);
    40     sz[x]=sz[ls[x]]+sz[rs[x]]; sm[x]=sm[ls[x]]+sm[rs[x]];
    41     return res;
    42 }
    43 
    44 int merge(int x,int y,int L,int R){
    45     if (!x || !y) return x+y;
    46     sz[x]+=sz[y]; sm[x]+=sm[y];
    47     if (L<R){
    48         int mid=(L+R)>>1;
    49         ls[x]=merge(ls[x],ls[y],L,mid);
    50         rs[x]=merge(rs[x],rs[y],mid+1,R);
    51     }
    52     return x;
    53 }
    54 
    55 int find(int x,int L,int R,int k){
    56     if (L==R) return L;
    57     int mid=(L+R)>>1;
    58     if (k<=sz[ls[x]]) return find(lson,k);
    59         else return find(rson,k-sz[ls[x]]);
    60 }
    61 
    62 int main(){
    63     freopen("bzoj4399.in","r",stdin);
    64     freopen("bzoj4399.out","w",stdout);
    65     for (scanf("%d",&Q); Q--; ){
    66         scanf("%d",&op);
    67         if (op==1) scanf("%d",&x),n++,fa[n]=n,ins(rt[n],1,M,x,1);
    68         if (op==2){
    69             scanf("%d%d",&x,&y); int p=get(x),q=get(y);
    70             if (p==q) continue;
    71             rt[p]=merge(rt[p],rt[q],1,M); fa[q]=p;
    72         }
    73         if (op==3) scanf("%d%d",&x,&k),ins(rt[get(x)],1,M,k,mdf0(rt[get(x)],1,M,k));
    74         if (op==4) scanf("%d%d",&x,&k),ins(rt[get(x)],1,M,k,mdf1(rt[get(x)],1,M,k));
    75         if (op==5) scanf("%d%d",&x,&k),printf("%d
    ",find(rt[get(x)],1,M,k));
    76         if (op==6) scanf("%d%d",&x,&y),printf("%d
    ",(int)(sm[rt[get(x)]]>sm[rt[get(y)]]));
    77         if (op==7) scanf("%d",&x),printf("%d
    ",sz[rt[get(x)]]);
    78     }
    79     return 0;
    80 }
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  • 原文地址:https://www.cnblogs.com/HocRiser/p/9874098.html
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