python学习笔记——叁之修改配置文件

简单流程
循环输出 3个操作选项 读，修改，删除
输入 1  2  3
在得到输入的数字后 然后执行相应的方法


import os

def read():
    "读取"
    with open("haproxy.txt","r",encoding="utf-8") as r1 :
        list1= r1.readlines()


        for line in list1 :
           if "backend" in line :
               list1_index=list1.index(line)+1
               break

        list2=list1[list1_index:]
        for line_new in  list2 :
            print(line_new)

# def crtate(bakend,server,weight,maxconn):
def crtate(*args):
    "创建"
    with open("haproxy.txt","a+",encoding="utf_8") as a1:
        arg = {
            'bakend': args[0],
            'record': {
                'server': args[1],
                'weight': args[2],
                'maxconn': args[3]
            }
        }
        print(type(arg))
        for i in  arg :
            print(i,arg[i])
            if i=="record":
                 a1.write("
		"+str(arg.get("record")).replace("'","").replace("{"," ").
                          replace("}"," ").replace(":",""))
            else:
                a1.write("
"+str(i))
                a1.write(" "+str(arg[i]))
        a1.flush()

def  delete(x):
    "删除"
    with open("haproxy.txt","r",encoding="utf-8") as  d1 ,
        open("haproxy_new.txt","w",encoding="utf-8") as d2 :
        d1a=d1.readlines()
        for index,line in enumerate(d1a):
            if x in line :
                  print(index)
                  delete_index=index
        print(d1a[delete_index])
        print(d1a[delete_index+1])
        # d1.seek(0)
        d1a.pop(delete_index)
        d1a.pop(delete_index)
        for i in d1a :
            d2.write(i)
        os.rename("haproxy.txt","haproxy.bak")
        os.rename("haproxy_new.txt","haproxy.txt")

while True:
    q=input("请输入操作编号 1.读取 2.增加 3.删除>>")
    if q=="1":
        read()
    if q=="2":
        w=input("第一个>>>:")
        w1 = input("第二个>>>:")
        w2 = input("第三个>>>:")
        w3 = input("第四个>>>:")
        print(w,w1,w2,w3)
        crtate(w,w1,w2,w3)
    if q=="3":
        s=input("输入一个参数>>>")
        delete(s)