方法一:使用 sort.Slice() 进行排序
package main
import (
"fmt"
"sort"
)
type myStruct struct {
name string
score int
}
func main() {
s1 := []myStruct{
{name: "mcc", score: 1},
{name: "get", score: 2},
{name: "zp", score: 0},
}
fmt.Println("排序前:", s1)
sort.Slice(s1, func(i, j int) bool {
return s1[i].score < s1[j].score
})
fmt.Println("排序后:", s1)
}
方法二、使用sort.Sort() 进行排序
使用sort.Sort() 方法需要重写Len()、Swap()、Less() 这三个方法
package main
import (
"fmt"
"sort"
)
type myStruct struct {
name string
score int
}
type m2 []myStruct
func (a m2) Len() int {
return len(a)
}
func (a m2) Swap(i, j int) {
a[i], a[j] = a[j], a[i]
}
func (a m2) Less(i, j int) bool {
return a[i].score > a[j].score
}
func main() {
s2 := []myStruct{
{name: "mcc", score: 1},
{name: "get", score: 2},
{name: "zp", score: 0},
}
fmt.Println("排序前:", s2)
sort.Sort(m2(s2))
fmt.Println("排序后:", s2)
}