• HDU 1495 非常可乐


    非常可乐

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3654    Accepted Submission(s): 1522

    Problem Description
    大家一定觉的运动以后喝可乐是一件很惬意的事情,但是seeyou却不这么认为。因为每次当seeyou买了可乐以后,阿牛就要求和seeyou一起分享这一瓶可乐,而且一定要喝的和seeyou一样多。但seeyou的手中只有两个杯子,它们的容量分别是N 毫升和M 毫升 可乐的体积为S (S<101)毫升 (正好装满一瓶) ,它们三个之间可以相互倒可乐 (都是没有刻度的,且 S==N+M,101>S>0,N>0,M>0) 。聪明的ACMER你们说他们能平分吗?如果能请输出倒可乐的最少的次数,如果不能输出"NO"。
     
    Input
    三个整数 : S 可乐的体积 , N 和 M是两个杯子的容量,以"0 0 0"结束。
     
    Output
    如果能平分的话请输出最少要倒的次数,否则输出"NO"。
     
    Sample Input
    7 4 3
    4 1 3
    0 0 0
     
    Sample Output
    NO
    3
     
    Author
    seeyou
     
    Source
     
    Recommend
    LL
     
    思路:BFS,需要考虑的情况比较多,相比之下我的代码比较水,看类长路漫漫啊
     
    代码:
    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <queue>
    using namespace std;
    int hash[110][110][110];
    int s,n,m;
    struct Node
    {
        int s,n,m;
        int step;
    };
    int BFS()
    {
        queue <Node> q;
        Node top;top.s = s;top.n = 0;top.m = 0;top.step = 0;
        q.push(top);
        while(!q.empty())
        {
            Node temp = q.front();q.pop();
            if(temp.s == s / 2 && (temp.n == s / 2 || temp.m == s / 2))
                      return temp.step;
            if(temp.n == s / 2 && (temp.s == s / 2 || temp.m == s / 2))
                      return temp.step;
            if(temp.m == s / 2 && (temp.s == s / 2 || temp.n == s / 2))
                      return temp.step;
            //printf("%d %d %d have %d ",temp.s,temp.n,temp.m,temp.step);
            if(temp.s != 0)
            {
                if(temp.n != n)
                {
                    int x = temp.s;int y = temp.n;int z = temp.m;int step = temp.step;
                    //printf("%d %d %d have %d ",temp.s,temp.n,temp.m,temp.step);
                    if(y + x <= n)
                    {
                        y = x + y;
                        x = 0;
                        z = z;
                        step = step + 1;
                    }
                    else
                    {
                        x = x - (n - y);
                        y = n;
                        z = z;
                        step = step + 1;
                    }
                    if(hash[x][y][z] == 0)
                    {
                      Node xin;xin.s = x;xin.n = y;xin.m = z;xin.step = step;
                      q.push(xin);
                      //printf("%d %d %d have %d ",x,y,z,step);
                      hash[x][y][z] = 1;
                    }
                }
                if(temp.m != m)
                {
                    int x = temp.s;int y = temp.n;int z = temp.m;int step = temp.step;
                    if(z + x <= m)
                    {
                        z = x + z;
                        x = 0;
                        y = y;
                        step = step + 1;
                    }
                    else
                    {
                        x = x - (m - z);
                        z = m;
                        y = y;
                        step = step + 1;
                    }
                    if(hash[x][y][z] == 0)
                    {
                      Node xin;xin.s = x;xin.n = y;xin.m = z;xin.step = step;
                      q.push(xin);
                      //printf("%d %d %d have %d ",x,y,z,step);
                      hash[x][y][z] = 1;
                    }
                 }
             }
             if(temp.n != 0)
             {
                if(temp.s != s)
                {
                    int x = temp.s;int y = temp.n;int z = temp.m;int step = temp.step;
                    if(y + x <= s)
                    {
                        x = x + y;
                        y = 0;
                        z = z;
                        step = step + 1;
                    }
                    else
                    {
                        y = y - (s - x);
                        x = s;
                        z = z;
                        step = step + 1;
                    }
                    if(hash[x][y][z] == 0)
                    {
                      Node xin;xin.s = x;xin.n = y;xin.m = z;xin.step = step;
                      q.push(xin);
                      //printf("%d %d %d have %d ",x,y,z,step);
                      hash[x][y][z] = 1;
                    }
                }
                if(temp.m != m)
                {
                    int x = temp.s;int y = temp.n;int z = temp.m;int step = temp.step;
                    if(z + y <= m)
                    {
                        z = y + z;
                        y = 0;
                        x = x;
                        step = step + 1;
                    }
                    else
                    {
                        y = y - (m - z);
                        z = m;
                        x = x;
                        step = step + 1;
                    }
                    if(hash[x][y][z] == 0)
                    {
                      Node xin;xin.s = x;xin.n = y;xin.m = z;xin.step = step;
                      q.push(xin);
                      ///printf("%d %d %d have %d ",x,y,z,step);
                      hash[x][y][z] = 1;
                    }
                 }
             }
             if(temp.m != 0)
            {
                if(temp.n != n)
                {
                    int x = temp.s;int y = temp.n;int z = temp.m;int step = temp.step;
                    if(y + z <= n)
                    {
                        y = z + y;
                        z = 0;
                        x = x;
                        step = step + 1;
                    }
                    else
                    {
                        z = z - (n - y);
                        y = n;
                        x = x;
                        step = step + 1;
                    }
                    if(hash[x][y][z] == 0)
                    {
                       Node xin;xin.s = x;xin.n = y;xin.m = z;xin.step = step;
                       q.push(xin);
                       //printf("%d %d %d have %d ",x,y,z,step);
                       hash[x][y][z]  = 1;
                    }
                }
                if(temp.s != s)
                {
                    int x = temp.s;int y = temp.n;int z = temp.m;int step = temp.step;
                    if(z + x <= s)
                    {
                        x = x + z;
                        z = 0;
                        y = y;
                        step = step + 1;
                    }
                    else
                    {
                        z = z - (s - x);
                        x = s;
                        y = y;
                        step = step + 1;
                    }
                    if(hash[x][y][z] == 0)
                    {
                      Node xin;xin.s = x;xin.n = y;xin.m = z;xin.step = step;
                      q.push(xin);
                      //printf("%d %d %d have %d ",x,y,z,step);
                      hash[x][y][z] = 1;
                    }
                 }
            }
        }
        return -1;
    }            
    int main()
    {
        while(scanf("%d%d%d",&s,&n,&m),s != 0 && n != 0 && m != 0)
        {
            memset(hash,0,sizeof(hash));
            hash[s][n][m] = 1;
            int sss = BFS();
            if(s % 2 == 1)
               sss = -1;
            if(sss == -1)
                printf("NO ");
            else
                printf("%d ",sss);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/GODLIKEING/p/3286285.html
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