• Leetcode: Insert Delete GetRandom O(1)


    Design a data structure that supports all following operations in average O(1) time.
    
    Note: Duplicate elements are allowed.
    insert(val): Inserts an item val to the collection.
    remove(val): Removes an item val from the collection if present.
    getRandom: Returns a random element from current collection of elements. The probability of each element being returned is linearly related to the number of same value the collection contains.
    Example:
    
    // Init an empty collection.
    RandomizedCollection collection = new RandomizedCollection();
    
    // Inserts 1 to the collection. Returns true as the collection did not contain 1.
    collection.insert(1);
    
    // Inserts another 1 to the collection. Returns false as the collection contained 1. Collection now contains [1,1].
    collection.insert(1);
    
    // Inserts 2 to the collection, returns true. Collection now contains [1,1,2].
    collection.insert(2);
    
    // getRandom should return 1 with the probability 2/3, and returns 2 with the probability 1/3.
    collection.getRandom();
    
    // Removes 1 from the collection, returns true. Collection now contains [1,2].
    collection.remove(1);
    
    // getRandom should return 1 and 2 both equally likely.
    collection.getRandom();

    The idea is to add a set to the hashMap to remember all the locations of a duplicated number.

     1 public class RandomizedCollection {
     2     HashMap<Integer, HashSet<Integer>> map;
     3     ArrayList<Integer> arr;
     4     java.util.Random random;
     5 
     6     /** Initialize your data structure here. */
     7     public RandomizedCollection() {
     8         map = new HashMap<Integer, HashSet<Integer>>();
     9         arr = new ArrayList<Integer>();
    10         random = new java.util.Random();
    11     }
    12     
    13     /** Inserts a value to the collection. Returns true if the collection did not already contain the specified element. */
    14     public boolean insert(int val) {
    15         boolean res = false;
    16         if (!map.containsKey(val)) {
    17             map.put(val, new HashSet<Integer>());
    18             res = true;
    19         }
    20         arr.add(val);
    21         map.get(val).add(arr.size()-1);
    22         return res;
    23     }
    24     
    25     /** Removes a value from the collection. Returns true if the collection contained the specified element. */
    26     public boolean remove(int val) {
    27         if (!map.containsKey(val)) return false;
    28         int lastItem = arr.get(arr.size()-1);
    29         int index = arr.size()-1;
    30         if (lastItem != val) {
    31             HashSet<Integer> lastItemSet = map.get(lastItem);
    32             index = map.get(val).iterator().next();
    33             arr.set(index, lastItem);
    34             lastItemSet.remove(arr.size()-1);
    35             lastItemSet.add(index);
    36         }
    37         
    38         if (map.get(val).size() == 1) map.remove(val);
    39         else map.get(val).remove(index);
    40         arr.remove(arr.size()-1);
    41         return true;
    42     }
    43     
    44     /** Get a random element from the collection. */
    45     public int getRandom() {
    46         return arr.get(random.nextInt(arr.size()));
    47     }
    48 }
    49 
    50 /**
    51  * Your RandomizedCollection object will be instantiated and called as such:
    52  * RandomizedCollection obj = new RandomizedCollection();
    53  * boolean param_1 = obj.insert(val);
    54  * boolean param_2 = obj.remove(val);
    55  * int param_3 = obj.getRandom();
    56  */
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  • 原文地址:https://www.cnblogs.com/EdwardLiu/p/6112083.html
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