题目:平面上给定n条线段,找出一个点,使这个点到这n条线段的距离和最小。
源码如下:
1 #include <iostream> 2 #include <string.h> 3 #include <stdlib.h> 4 #include <stdio.h> 5 #include <time.h> 6 #include <math.h> 7 8 #define N 1005 9 #define eps 1e-8 //搜索停止条件阀值 10 #define INF 1e99 11 #define delta 0.98 //温度下降速度 12 #define T 100 //初始温度 13 14 using namespace std; 15 16 int dx[4] = {0, 0, -1, 1}; 17 int dy[4] = {-1, 1, 0, 0}; //上下左右四个方向 18 19 struct Point 20 { 21 double x, y; 22 }; 23 24 Point s[N], t[N]; 25 26 double cross(Point A, Point B, Point C) 27 { 28 return (B.x - A.x) * (C.y - A.y) - (B.y - A.y) * (C.x - A.x); 29 } 30 31 double multi(Point A, Point B, Point C) 32 { 33 return (B.x - A.x) * (C.x - A.x) + (B.y - A.y) * (C.y - A.y); 34 } 35 36 double dist(Point A, Point B) 37 { 38 return sqrt((A.x - B.x) * (A.x - B.x) + (A.y - B.y) * (A.y - B.y)); 39 } 40 41 double GetDist(Point A, Point B, Point C) 42 { 43 if(dist(A, B) < eps) return dist(B, C); 44 if(multi(A, B, C) < -eps) return dist(A, C); 45 if(multi(B, A, C) < -eps) return dist(B, C); 46 return fabs(cross(A, B, C) / dist(A, B)); 47 } 48 49 double GetSum(Point s[], Point t[], int n, Point o) 50 { 51 double ans = 0; 52 while(n--) 53 ans += GetDist(s[n], t[n], o); 54 return ans; 55 } 56 57 double Search(Point s[], Point t[], int n, Point &o) 58 { 59 o = s[0]; 60 double tem = T; 61 double ans = INF; 62 while(tem > eps) 63 { 64 bool flag = 1; 65 while(flag) 66 { 67 flag = 0; 68 for(int i = 0; i < 4; i++) //上下左右四个方向 69 { 70 Point z; 71 z.x = o.x + dx[i] * tem; 72 z.y = o.y + dy[i] * tem; 73 double tp = GetSum(s, t, n, z); 74 if(ans > tp) 75 { 76 ans = tp; 77 o = z; 78 flag = 1; 79 } 80 } 81 } 82 tem *= delta; 83 } 84 return ans; 85 } 86 87 int main() 88 { 89 int n; 90 while(scanf("%d", &n) != EOF) 91 { 92 for(int i = 0; i < n; i++) 93 scanf("%lf %lf %lf %lf", &s[i].x, &s[i].y, &t[i].x, &t[i].y); 94 Point o; 95 double ans = Search(s, t, n, o); 96 printf("%.1lf %.1lf %.1lf ", o.x, o.y, ans); 97 } 98 return 0; 99 }