代码:
def count_number(target_str): d = {} for i in target_str: if i in d: d[i] += 1 else: d[i] = 1 return d
测试:
s = "jgiwejgiwiwrijhiwrihowWrohwrih" print(count_number(s))
结果:
{'j': 3, 'g': 2, 'i': 7, 'w': 6, 'e': 1, 'r': 4, 'h': 4, 'o': 2, 'W': 1}