• IntelliJ IDEA 14.0.2破解注册码文件(2015年06月08日)


    Java文件代码:

    import java.math.BigInteger;
    import java.util.Date;
    import java.util.Random;
    import java.util.Scanner;
    import java.util.zip.CRC32;
    public class KeyGen {
    public static short getCRC(String s, int i, byte bytes[]){
    CRC32 crc32 = new CRC32();
    if (s != null)
    {
    for (int j = 0; j < s.length(); j++)
    {
    char c = s.charAt(j);
    crc32.update(c);
    }
    }
    crc32.update(i);
    crc32.update(i >> 8);
    crc32.update(i >> 16);
    crc32.update(i >> 24);
    for (int k = 0; k < bytes.length - 2; k++)
    {
    byte byte0 = bytes[k];
    crc32.update(byte0);
    }
    return (short) (int) crc32.getValue();
    }

    public static String encodeGroups(BigInteger biginteger){
    BigInteger beginner1 = BigInteger.valueOf(0x39aa400L);
    StringBuilder sb = new StringBuilder();
    for (int i = 0; biginteger.compareTo(BigInteger.ZERO) != 0; i++)
    {
    int j = biginteger.mod(beginner1).intValue();
    String s1 = encodeGroup(j);
    if (i > 0)
    {
    sb.append("-");
    }
    sb.append(s1);
    biginteger = biginteger.divide(beginner1);
    }
    return sb.toString();
    }

    public static String encodeGroup(int i){
    StringBuilder sb = new StringBuilder();
    for (int j = 0; j < 5; j++)
    {
    int k = i % 36;
    char c;
    if (k < 10)
    {
    c = (char) (48 + k);
    }
    else
    {
    c = (char) ((65 + k) - 10);
    }
    sb.append(c);
    i /= 36;
    }
    return sb.toString();
    }

    public static String MakeKey(String name, int days, int id){
    id %= 100000;
    byte bkey[] = new byte[12];
    bkey[0] = (byte) 1; // Product type: IntelliJ IDEA is 1
    bkey[1] = 14; // version
    Date d = new Date();
    long ld = (d.getTime() >> 16);
    bkey[2] = (byte) (ld & 255);
    bkey[3] = (byte) ((ld >> 8) & 255);
    bkey[4] = (byte) ((ld >> 16) & 255);
    bkey[5] = (byte) ((ld >> 24) & 255);
    days &= 0xffff;
    bkey[6] = (byte) (days & 255);
    bkey[7] = (byte) ((days >> 8) & 255);
    bkey[8] = 105;
    bkey[9] = -59;
    bkey[10] = 0;
    bkey[11] = 0;
    int w = getCRC(name, id % 100000, bkey);
    bkey[10] = (byte) (w & 255);
    bkey[11] = (byte) ((w >> 8) & 255);
    BigInteger pow = new BigInteger("89126272330128007543578052027888001981", 10);
    BigInteger mod = new BigInteger("86f71688cdd2612ca117d1f54bdae029", 16);
    BigInteger k0 = new BigInteger(bkey);
    BigInteger k1 = k0.modPow(pow, mod);
    String s0 = Integer.toString(id);
    String sz = "0";
    while (s0.length() != 5)
    {
    s0 = sz.concat(s0);
    }
    s0 = s0.concat("-");
    String s1 = encodeGroups(k1);
    s0 = s0.concat(s1);
    return s0;
    }

    public static void main(String[] args){
    System.out.println("请输入用户名:");
    Scanner scanner = new Scanner(System.in);
    String username = scanner.next();
    Random r = new Random();
    System.out.println(MakeKey(username, 0, r.nextInt(100000)));
    }
    }

    运行这段代码即可得到破解码

    01n49jrmb95%m`]_lzy2p34

    cyf304z%@r~w7dbqwtlnn@e

    不知道对其他的版本支不支持,有兴趣的可以试试......

  • 相关阅读:
    libevent网络编程汇总
    LibEvent代码阅读--多缓冲区和零拷贝技术
    几个第三方库发图片
    Libevent使用例子,从简单到复杂
    CImage得到位图的大小
    从位图数据取得位图句柄
    BMP格式详解
    如何将内存中的位图数据绘制在DC上
    C++加载位图跟SOCKET通信的编写
    11235
  • 原文地址:https://www.cnblogs.com/Dreyer/p/4562301.html
Copyright © 2020-2023  润新知