• Picnic Planning POJ


    5000+B,调死我了

    set里判重居然是用符号比较判的,调出这个问题之后又莫名re,maxn改到3000居然才能跑discuss的样例

    后来本机测发现弹了个bad_alloc。。看来以后做题vector不能随便开这么多了,估计改成静态数组每个一个tot就可以maxn30了

      1 //#include<bits/stdc++.h>  
      2 //#pragma comment(linker, "/STACK:1024000000,1024000000")   
      3 #include<stdio.h>  
      4 #include<algorithm>  
      5 #include<queue>  
      6 #include<string.h>  
      7 #include<iostream>  
      8 #include<math.h>                    
      9 #include<stack>
     10 #include<set>  
     11 #include<map>  
     12 #include<vector>  
     13 #include<iomanip> 
     14 #include<bitset>
     15 using namespace std;         //
     16 
     17 #define ll long long  
     18 #define ull unsigned long long
     19 #define pb push_back  
     20 #define FOR(a) for(int i=1;i<=a;i++) 
     21 #define sqr(a) (a)*(a)
     22 #define dis(a,b) sqrt(sqr(a.x-b.x)+sqr(a.y-b.y))
     23 ll qp(ll a,ll b,ll mod){
     24     ll t=1;while(b){if(b&1)t=t*a%mod;b>>=1;a=a*a%mod;}return t;
     25 }
     26 struct DOT{int x;int y;};
     27 inline void read(int &x){int k=0;char f=1;char c=getchar();for(;!isdigit(c);c=getchar())if(c=='-')f=-1;for(;isdigit(c);c=getchar())k=k*10+c-'0';x=k*f;} 
     28 void ex(){puts("No");exit(0);}
     29 const int dx[4]={0,0,-1,1};
     30 const int dy[4]={1,-1,0,0};
     31 const int inf=0x3f3f3f3f; 
     32 const ll Linf=0x3f3f3f3f3f3f3f3fLL;
     33 const ll Mod=1e18+7;
     34 
     35 const int maxn=3300;
     36 
     37 int n,lim;
     38 map<string,int>idx;
     39 char buf[2][15];
     40 int tot;
     41 int edgcnt;
     42 
     43 struct EDGE{
     44     int u,v,w;
     45     bool del;
     46     int id;
     47     friend bool operator <(EDGE A,EDGE B){return A.w<B.w;}
     48 };
     49 set<int>DES;
     50 vector<EDGE>G[maxn];
     51 vector<EDGE>T[maxn];    //树图
     52 
     53 int belong[maxn];
     54 vector<int>hav[maxn];
     55 int blkcnt;
     56 int root;
     57 
     58 int fa[maxn];
     59 void init(int n){for(int i=1;i<=n;i++)fa[i]=i;}
     60 int find(int x){return fa[x]==x?x:fa[x]=find(fa[x]);}
     61 void unite(int x,int y){x=find(x);y=find(y);fa[x]=y;}
     62 
     63 vector<EDGE>BLK;
     64 
     65 void dfs(int x,int fa){
     66     if(belong[x])return;
     67     belong[x]=blkcnt;
     68     hav[blkcnt].pb(x);
     69     for(int i=0;i<G[x].size();i++){
     70         int v=G[x][i].v,w=G[x][i].w;
     71         if(v==fa)continue;
     72         if(v==root)continue;
     73         dfs(v,x);
     74     }
     75 }
     76 
     77 
     78 int ans;
     79 
     80 set<int>SSS;    //park连接的点
     81 int du;            //root的度数
     82 
     83 struct NODE{
     84     EDGE del;
     85     int val;
     86     int to;
     87     int newLen;    //
     88     friend bool operator<(NODE A,NODE B){
     89         return A.val<B.val;
     90     }
     91 };
     92 
     93 int flag;
     94 
     95 void dfsx(int u,int fa,int &mxlen,EDGE &remo,int gf){
     96     //if(ans==82 && gf==6){
     97     //    cout<<u<<"路径"<<T[6].size()<<endl;
     98     //}
     99     if(u==root){
    100         flag=1;return;
    101     }
    102 
    103 
    104     for(int i=0;i<T[u].size();i++){
    105 
    106         if(DES.count(T[u][i].id))continue;
    107 
    108         //if(ans==82 && gf==6 && u==6){
    109         //    cout<<"goto"<<T[u][i].v<<"ww"<<i<<endl;
    110         //}
    111 
    112 
    113         int v=T[u][i].v,w=T[u][i].w;
    114         if(v==fa)continue;
    115 
    116         int tmplen=mxlen;
    117         EDGE tmpremo=remo;
    118 
    119         if(mxlen<w){
    120             mxlen=w;
    121             remo=T[u][i];
    122         }
    123 
    124         dfsx(v,u,mxlen,remo,gf);
    125 
    126         if(!flag){
    127             mxlen=tmplen;
    128             remo=tmpremo;
    129         }else{
    130             return;
    131         }
    132     }
    133 }
    134 
    135 int main(){
    136     while(~scanf("%d",&n)){
    137 
    138         int x;
    139         lim=0;
    140         tot=0;blkcnt=0;ans=0;du=0;edgcnt=0;root=0;
    141 
    142         for(int i=0;i<=32;i++){
    143             G[i].clear();T[i].clear();
    144             hav[i].clear();
    145         }
    146         du=0;BLK.clear();SSS.clear();DES.clear();
    147         memset(belong,0,sizeof belong);idx.clear();
    148         flag=0;
    149 
    150 
    151         
    152         //idx["Park"]=8;
    153         //idx["1"]=1;idx["2"]=2;
    154         //idx["3"]=3;idx["4"]=4;
    155         //idx["5"]=5;idx["6"]=6;
    156         //idx["7"]=7;idx["8"]=8;
    157         //tot=8;    
    158 
    159 
    160 
    161         for(int i=1;i<=n;i++){
    162             scanf("%s%s%d",buf[0]+1,buf[1]+1,&x);
    163 
    164             
    165             if(idx[buf[0]+1]==0){
    166                 idx[buf[0]+1]=++tot;
    167             }
    168             if(idx[buf[1]+1]==0){
    169                 idx[buf[1]+1]=++tot;
    170             }
    171             
    172 
    173             int u=idx[buf[0]+1],v=idx[buf[1]+1];
    174 
    175             //cout<<u<<"ww"<<v<<endl;
    176 
    177             int w=x;
    178 
    179             G[idx[buf[0]+1]].pb((EDGE){u,v,w,false,edgcnt++});
    180             G[idx[buf[1]+1]].pb((EDGE){v,u,w,false,edgcnt++});
    181         }
    182         scanf("%d",&lim);
    183 
    184         root=idx["Park"];
    185         for(int i=1;i<=tot;i++){
    186             if(!belong[i] && i!=root){
    187                 ++blkcnt;
    188                 dfs(i,i);
    189             }
    190         }
    191         
    192         init(tot);
    193 
    194         for(int i=1;i<=blkcnt;i++){
    195             int mnlen=inf,toid=0;
    196 
    197             BLK.clear();
    198             for(int j=0;j<hav[i].size();j++){
    199                 for(int k=0;k<G[hav[i][j]].size();k++){
    200                     int v=G[hav[i][j]][k].v,w=G[hav[i][j]][k].w;
    201                     if(v!=root)BLK.pb(G[hav[i][j]][k]);
    202                     else{
    203                         if(w<mnlen){
    204                             mnlen=w;
    205                             toid=hav[i][j];
    206                         }
    207                     }
    208                 }
    209             }
    210 
    211             sort(BLK.begin(),BLK.end());
    212 
    213             for(int j=0;j<BLK.size();j++){
    214                 int x=BLK[j].u,y=BLK[j].v;
    215                 x=find(x);y=find(y);
    216                 if(x==y)continue;
    217                 else{
    218                     unite(x,y);
    219                     ans+=BLK[j].w;
    220                     
    221                     x=BLK[j].u;
    222                     y=BLK[j].v;
    223 
    224                     T[x].pb((EDGE){x,y,BLK[j].w,false,edgcnt++});
    225                     T[y].pb((EDGE){y,x,BLK[j].w,false,edgcnt++});
    226 
    227                     //cout<<x<<" "<<y<<" "<<BLK[j].w<<endl;
    228                 }
    229             }
    230 
    231             //cout<<toid<<"www"<<mnlen<<endl;
    232 
    233             //cout<<ans<<"ww"<<endl;exit(0);
    234             //选代表元素
    235             T[root].pb((EDGE){root,toid,mnlen,false,edgcnt++});
    236             T[toid].pb((EDGE){toid,root,mnlen,false,edgcnt++});
    237 
    238             ans+=mnlen;
    239             SSS.insert(toid);
    240             du++;
    241         }
    242 
    243         while(du<lim){
    244             priority_queue<NODE>Q;
    245 
    246             for(int i=0;i<G[root].size();i++){        
    247                 
    248                 int v=G[root][i].v,w=G[root][i].w;
    249                 if(SSS.count(v))continue;
    250                 EDGE plc;
    251                 int vvl=0;
    252 
    253                 flag=0;
    254 
    255                 dfsx(v,v,vvl,plc,v);    //v到root的路径找最长边
    256                 
    257                 //if(ans==82){
    258                 //    cout<<v<<"ww"<<plc.u<<"__"<<plc.v<<endl;
    259                 //}
    260 
    261                 Q.push((NODE){plc,vvl-w,v,w});
    262             }
    263             if(Q.empty())break;
    264             NODE now=Q.top();
    265             if(now.val<0)break;
    266             ans-=now.val;
    267 
    268             //cout<<now.to<<"ww"<<now.newLen<<"ww"<<now.val<<"ww"<<ans<<endl;
    269             //cout<<now.del.u<<"ww"<<now.del.v<<endl;
    270 
    271             T[root].pb((EDGE){root,now.to,now.newLen,edgcnt++});
    272             T[now.to].pb((EDGE){now.to,root,now.newLen,edgcnt++});
    273 
    274             //cout<<du<<"du"<<now.to<<"qqq"<<root<<endl;
    275 
    276             SSS.insert(now.to);
    277             DES.insert(now.del.id);
    278             DES.insert(now.del.id^1);
    279             
    280             du++;
    281         }
    282         printf("Total miles driven: %d
    ",ans);
    283     }    
    284 }
    View Code
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  • 原文地址:https://www.cnblogs.com/Drenight/p/8656401.html
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