• 【HDU1875】畅通工程再续(MST基础题)


    更改成实形数即可。第一次敲完直接交,CE了一次。晕。

     1 #include <iostream>
     2 #include <cstring>
     3 #include <cstdio>
     4 #include <cstdio>
     5 #include <cctype>
     6 #include <cmath>
     7 #include <algorithm>
     8 #include <numeric>
     9 
    10 #define typec double
    11 using namespace std;
    12 
    13 const typec inf = 0xffff;
    14 const int V = 1005;
    15 int vis[V];
    16 typec lowc[V], Map[V][V], point[V][2];
    17 
    18 typec prim (typec cost[][V], int n) {
    19     int i, j, p;
    20     typec minc, res = 0;
    21     memset(vis, 0, sizeof(vis));
    22     vis[0] = 1;
    23     for (i = 1; i < n; ++ i) lowc[i] = cost[0][i];
    24     for (i = 1; i < n; ++ i) {
    25         minc = inf; p = -1;
    26         for (j = 0; j < n; ++ j ) {
    27             if (0 == vis[j] && minc > lowc[j]) {
    28                 minc = lowc[j];
    29                 p = j;
    30             }
    31         }
    32         if (inf == minc) return -1;
    33         res += minc;
    34         vis[p] = 1;
    35         for (j = 0; j < n; ++ j) {
    36             if (0 == vis[j] && lowc[j] > cost[p][j]) {
    37                 lowc[j] = cost[p][j];
    38             }
    39         }
    40     }
    41     return res;
    42 }
    43 
    44 double cal_dis (double x1, double y1, double x2, double y2) {
    45     return sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2));
    46 }
    47 
    48 int main () {
    49     int T; scanf("%d", &T);
    50     while (T --) {
    51         //vector<pair<double, double> > p;
    52         int n; scanf("%d", &n);
    53         for (int i = 0; i < n; ++ i) {
    54             scanf("%lf%lf", &point[i][0], &point[i][1]);
    55         }
    56 
    57         for (int i = 0 ; i < 105; ++ i) {
    58             for (int j = 0; j < 105; ++ j) {
    59                 if (i == j) Map[i][j] = 0;
    60                 else Map[i][j] = inf;
    61             }
    62         }
    63 
    64         for (int i = 0; i < n; ++i) {
    65             for (int j = i + 1; j < n; ++ j) {
    66                 double w = cal_dis(point[i][0], point[i][1],point[j][0],point[j][1]);
    67                 if (w >= 10 && w <= 1000)
    68                     Map[i][j] = Map[j][i] = min(Map[i][j], w);
    69                 else continue;
    70                 /*cout << Map[i][j] << endl;
    71                 cout << Map[j][i] << endl;*/
    72             }
    73         }
    74 
    75         /*for (int i = 0; i < 2; ++ i) {
    76             for (int j = 0 ; j < 2; ++ j) {
    77                 cout << Map[i][j] << " ";
    78             }
    79             cout << endl;
    80         }*/
    81         double ans = 100 * prim(Map, n);
    82         if (ans > 0)
    83             printf("%.1lf
    ", ans);
    84         else {
    85             printf("oh!
    ");
    86         }
    87         //cout << prim (Map, n) << endl;
    88     }
    89     return 0;
    90 }
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  • 原文地址:https://www.cnblogs.com/Destiny-Gem/p/3865437.html
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