• bzoj 4349: 最小树形图


    最小树形图模板题……

    这种(O(nm))的东西真的能考到么……

    #include <bits/stdc++.h>
    #define N 60
    #define INF 1000000000
    using namespace std;
    int n, m, nn;
    double ai[N], an[N], ci[2][N][N], ans;
    int bc[N];
    int ini[N], vis[N], inc[N], inl[N];
    int dfn;
    int dfs(int t)
    {
        vis[t] = dfn;
        if (vis[ini[t]] == vis[t])
            return ini[t];
        else if (vis[ini[t]]) 
            return 0;
        else return dfs(ini[t]);
    }
     
    int main()
    {
        scanf("%d", &n);
        for (int i = 0; i <= n; ++ i)
            for (int j = 0; j <= n; ++ j)
                ci[0][i][j] = INF;
        for (int i = 1; i <= n; ++ i)
            scanf("%lf%d", &ai[i], &bc[i]), an[i] = ai[i], ci[0][0][i] = ai[i];
        scanf("%d", &m);
        for (int i = 1; i <= m; ++ i)
        {
            int a, b; double c;
            scanf("%d%d%lf", &a, &b, &c);
            if (a != b) ci[0][a][b] = min(ci[0][a][b], c);
            an[b] = min(an[b], c);
        }
        for (int i = 1; i <= n; ++ i) ans += an[i] * (bc[i] - 1);
        int tmp = 0, wh = 1; nn = n;
        while (wh)
        {
            wh = 0;
            for (int i = 1; i <= nn; ++ i)
            {
                double mn = INF;
                for (int j = 0; j <= nn; ++ j)
                    if (ci[tmp][j][i] < mn)
                        mn = ci[tmp][j][i], ini[i] = j;
            }
            for (int i = 0; i <= nn; ++ i) vis[i] = 0; vis[0] = -1;
            for (int i = 1; i <= nn; ++ i)
                if (!vis[i])
                {
                    dfn ++;
                    int x = dfs(i);
                    if (x)
                    {
                        int tot = 0;
                        wh = 1;
                        for (int j = 0; j <= nn; ++ j) inc[j] = 0;
                        for (int j = ini[x]; j != x; j = ini[j]) inc[j] = 1; inc[x] = 1;
                        for (int j = 0; j <= nn; ++ j) if (!inc[j]) inl[j] = tot ++; else ans += ci[tmp][ini[j]][j];
                        for (int j = 0; j <= nn; ++ j)
                            for (int k = 0; k <= nn; ++ k)
                                ci[!tmp][j][k] = INF;
                        for (int j = 0; j <= nn; ++ j)
                            for (int k = 0; k <= nn; ++ k)
                            {
                                if (!inc[j])
                                {
                                    if (!inc[k])
                                        ci[!tmp][inl[j]][inl[k]] = min(ci[!tmp][inl[j]][inl[k]], ci[tmp][j][k]);
                                    else
                                        ci[!tmp][inl[j]][tot] = min(ci[!tmp][inl[j]][tot], ci[tmp][j][k] - ci[tmp][ini[k]][k]);
                                }
                                else if (!inc[k])
                                        ci[!tmp][tot][inl[k]] = min(ci[!tmp][tot][inl[k]], ci[tmp][j][k]);
                            }
                        nn = tot;
                        break;
                    }
                }
            if (!wh)
                for (int i = 1; i <= nn; ++ i) ans += ci[tmp][ini[i]][i];
            else tmp ^= 1;
        }
        printf("%.2lf", ans);
    }
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  • 原文地址:https://www.cnblogs.com/AwD-/p/6254155.html
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