• [Functional Programming + React] Provide a reasonable default value for mapStateToProps in case initial state is undefined


    For example we have a component, it needs to call 'react-redux' connect function.

    import { compose, curry, option, propPath } from '../js/helper'
    
    const FilterButton = ({ active, onClick }) => {
        const classes = classnames('filterButton', {
            'filterButton--active': active
        })
        return <Button className={classes} onClick={onClick} icon={faFilter} />
    }
    
    FilterButton.defaultProps = {
        active: true,
        onClick: Function.prototype
    }
    
    FilterButton.propTypes = {
        active: PropTypes.bool,
        group: PropTypes.string.isRequired,
        onClick: PropTypes.func
    }
    
    const mapStateToProps = (state, ownProps) => ({
        active: state.ui.filterGroups[ownProps.group]
    })
    
    export default connect(mapStateToProps)(FilterButton)

    For the hightlighted part, there can be many possible reason for it to go wrong. We can use Maybe to provide a reasonable default value.

    First, the inital State is:

    const data = {
        nextId: 4,
        todoFilter: 'SHOW_ALL',
        todos: [
           ...
        ],
        ui: {
            filterGroups: {
                status: false
            }
        }
    }

    If the highlighted part is undefined, we still want it works.

    import { chain, compose, curry, isBoolean, option, propPath, safe } from 'crocks'
    ...
    
    const activeGroup = curry(group =>
        compose(
            option(FilterButton.defaultProps.active),
    chain(safe(isBoolean)), propPath([
    'ui', 'filterGroups', group]) ) ) const mapStateToProps = (state, ownProps) => ({ active: activeGroup(ownProps.group, state) }) export default connect(mapStateToProps)(FilterButton)

    The reason to put a chain() there is because, if the initial state is not boolean but string value, we can do safe type check, to make sure, what we got is Boolean value in the end, it not a Boolean, then Option() will set it to false. 

    --Full code--

    import React from 'react'
    import PropTypes from 'prop-types'
    import { connect } from 'react-redux'
    import Button from './controls/Button'
    import classnames from 'classnames'
    import { faFilter } from '@fortawesome/free-solid-svg-icons'
    
    import { chain, compose, curry, isBoolean, option, propPath, safe } from 'crocks'
    
    const FilterButton = ({ active, onClick }) => {
        const classes = classnames('filterButton', {
            'filterButton--active': active
        })
        return <Button className={classes} onClick={onClick} icon={faFilter} />
    }
    
    FilterButton.defaultProps = {
        active: true,
        onClick: Function.prototype
    }
    
    FilterButton.propTypes = {
        active: PropTypes.bool,
        group: PropTypes.string.isRequired,
        onClick: PropTypes.func
    }
    
    const activeGroup = curry(group =>
        compose(
            option(FilterButton.defaultProps.active),
    chain(safe(isBoolean)), propPath([
    'ui', 'filterGroups', group]) ) ) const mapStateToProps = (state, ownProps) => ({ active: activeGroup(ownProps.group, state) }) export default connect(mapStateToProps)(FilterButton)
  • 相关阅读:
    Task的用法
    C# 反射调用方法
    C#常用公共方法
    Spire.Doc for .NET(1)
    C#异常Retry通用类
    Java面试中经常遇到的类执行顺序
    Tensorflow学习教程集合
    SSD——样本正负比控制+多尺度检测 (目标检测)(one-stage)(深度学习)(ECCV 2016)
    SSD算法详解 及其 keras实现
    SSD原理解读-从入门到精通
  • 原文地址:https://www.cnblogs.com/Answer1215/p/10727119.html
Copyright © 2020-2023  润新知