NTT模板题
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<map>
#include<queue>
#include<vector>
#include<string>
#include<fstream>
using namespace std;
typedef long long ll;
const int N = 3e6 + 105;
const int mod = 998244353;
const double Pi = acos(- 1.0);
const int INF = 0x3f3f3f3f;
//NTT所需
const int G = 3, Gi = 332748118;
inline int read() {
char ch = getchar(); int x = 0, f = 1;
while (ch < '0' || ch > '9') {
if (ch == '-') f = -1;
ch = getchar();
}
while ('0' <= ch && ch <= '9') {
x = x * 10 + ch - '0';
ch = getchar();
} return x * f;
}
//NTT
int n, m, l, r[N];
int len = 1;
ll a[N], b[N];
inline ll qpow(ll a, ll b){
ll res = 1;
while(b){
if(b & 1) res = (res * a) % mod;
a = (a * a) % mod;
b >>= 1;
}
return res % mod;
}
inline void NTT(ll a[], int inv){
for(int i = 0; i < len; ++ i)
if(i < r[i])
swap(a[i], a[r[i]]);
for(int mid = 1; mid < len; mid <<= 1){
ll Wn = qpow(inv == 1 ? G : Gi , (mod - 1) / (mid << 1));
for(int Size = mid << 1, L = 0; L < len; L += Size){
ll w = 1;
for(int i = 0; i < mid; ++ i, w = (w * Wn) % mod){
int x = a[L + i], y = w * a[L + mid + i] % mod;
a[L + i] = (x + y) % mod;
a[L + mid + i] = (x - y + mod) % mod;
}
}
}
}
int main()
{
n = read(); m = read();
for(int i = 0; i <= n; ++ i) a[i] = (read() + mod) % mod;
for(int i = 0; i <= m; ++ i) b[i] = (read() + mod) % mod;
while(len <= n + m) len <<= 1, l ++;
for(int i = 0; i < len; ++ i)
r[i] = (r[i >> 1] >> 1 ) | ((i & 1) << (l - 1));
NTT(a, 1); NTT(b, 1);
for(int i = 0; i <= len; ++ i) a[i] = (a[i] * b[i]) % mod;
NTT(a, -1);
ll inv = qpow(len, mod - 2);
for(int i = 0; i <= n + m; ++ i)
printf("%d ", (a[i] * inv) % mod);
return 0;
}