从键盘任意输入a，b，c的值，编程计算并输出一元二次方程ax2+bx+c=0的根，当a=0时，输出“该方程不是一元二次方程”，当a≠0时，分b2−4ac>0、b2−4ac=0、b2−4ac<0三种情况计算并输出方程的根。
**输入格式要求："%f,%f,%f" 提示信息："Please enter the coefficients a,b,c:"
**输出格式要求："It is not a quadratic equation!
" "x1 = x2 = %.2f
" "x1 = %.2f, x2 = %.2f
"
"x1 = %.2f+%.2fi, " "x2 = %.2f-%.2fi
"
程序运行示例1如下：
Please enter the coefficients a,b,c:0,10,2
It is not a quadratic equation!
程序运行示例2如下：
Please enter the coefficients a,b,c:1,2,1
x1 = x2 = -1.00
程序运行示例3如下：
Please enter the coefficients a,b,c:2,3,2
x1 = -0.75+0.66i, x2 = -0.75-0.66i
变量定义为float类型，精度要求为1e-6，即
#define EPS 1e-6
1 #include<stdio.h>
2 #include<math.h>
3 #define EPS 1e-6
4 main() {
5 float a, b, c, d, x1, x2, i;
6 printf("Please enter the coefficients a,b,c:");
7 scanf("%f,%f,%f", &a, &b, &c);
8 d = b * b - 4 * a * c;
9 if (fabs(a)<=0)
10 printf("It is not a quadratic equation!
");
11 else
12 {
13 if (d<0)
14 {
15 x1 = -b / (2 * a);
16 i = sqrt(-d) / (2 * a);
17 printf("x1 = %.2f+%.2fi," , x1, i);
18 printf("x2 = %.2f-%.2fi
" , x1, i);
19 }
20 else if (fabs(d) > EPS)
21 {
22 x1 = (-b + sqrt(d)) / (2 * a);
23 x2 = (-b - sqrt(d)) / (2 * a);
24 printf("x1 = %.2f, x2 = %.2f
", x1, x2);
25 }
26 else if (fabs(d)<=EPS)
27 printf("x1 = x2 = %.2f
", -b / (2 * a));
28 }
29
30 }