四则运算倒计时第二版

题目要求：

　　1.学生写的程序必须能判定用户的输入答案是否正确

　　2.程序必须能处理四种运算的混合算式

　　3.要求两人合作分析，单独编程，单独撰写博客

    组员：朱子嘉  胡浩特（http://www.cnblogs.com/JYQ-hu/）

//四则运算3
//朱子嘉、胡浩特 2015/3/17

#include<iostream>
using namespace std;

#include<stdlib.h>
#include<time.h>
#include<math.h>
int display(int number, int mul, int num, int neg, int remainder)//打印方式控制输出列数
{
    int *a = new int[number];
    int *b = new int[number];
    int *c = new int[number];
    int *d = new int[number];
    int *e = new int[number];

    int m;//控制题目避免重复
    int t;//中间变量
    int n1 = 0;//保存正确题目数量
    int n2 = 0;//保存错误题目数量
    double result;//用户输入的题目结果
    for (int i = 0; i<number; i++)//随机生成运算操作数
    {
        m = 1;//初始化
        a[i] = rand() % num;
        b[i] = rand() % num;
        d[i] = rand() % num;
        e[i] = rand() % num;
        if (mul == 0)//没有乘除法
        {
            c[i] = rand() % 2;//随机生成0-1的数字，分别表示加减
        }
        else if (mul == 1)//有乘除法
        {
            c[i] =rand() % 8;//随机生成0-7的数字，分别表示不同运算符号组合
        }
        for (int j = 0; j<i; j++)
        {
            if (a[j] == a[i] && b[j] == b[i] && c[j] == c[i] && d[j] == d[i] && e[j] == e[i])//比较新生成的操作数与原来的是否相同
            {
                i = i - 1;
                m = 0;
            }
        }
        while (m)//若不同则输出
        {
            switch (c[i])
            {
            case 0:
                cout << a[i] << "+" << b[i] << "=" << endl;
                cout << "请输入结果:" << endl;
                cin >> result;
                if (result == a[i] + b[i])
                {
                    cout << "回答正确!" << endl;
                    n1++;
                }
                else
                {
                    cout << "回答错误!" << endl;
                    cout << "正确结果为：" << a[i] + b[i] << endl;
                    n2++;
                }
                break;
            case 1:
                if (neg == 0)//减法没有负数
                {
                    if (a[i]<b[i])
                    {
                        t = a[i];
                        a[i] = b[i];
                        b[i] = t;
                    }
                    cout << a[i] << "-" << b[i] << "=" << endl;
                    cout << "请输入结果:" << endl;
                    cin >> result;
                    if (result == a[i] - b[i])
                    {
                        cout << "回答正确!" << endl;
                        n1++;
                    }
                    else
                    {
                        cout << "回答错误!" << endl;
                        cout << "正确结果为：" << a[i] - b[i] << endl;
                        n2++;
                    }
                    break;
                }

                else if (neg == 1)//减法有负数
                {
                    cout << a[i] << "-" << b[i] << "=" << endl;
                    cout << "请输入结果:" << endl;
                    cin >> result;
                    if (result == a[i] - b[i])
                    {
                        cout << "回答正确!" << endl;
                        n1++;
                    }
                    else
                    {
                        cout << "回答错误!" << endl;
                        cout << "正确结果为：" << a[i] - b[i] << endl;
                        n2++;
                    }
                    break;
                }
            case 2:
                cout << a[i] << "+" << b[i] << "*" << d[i] << "-" << e[i] << "=" << endl;
                cout << "请输入结果:" << endl;
                cin >> result;
                if (result == a[i] + b[i] * d[i] - e[i])
                {
                    cout << "回答正确!" << endl;
                    n1++;
                }
                else
                {
                    cout << "回答错误!" << endl;
                    cout << "正确结果为：" << a[i] + b[i] * d[i] - e[i] << endl;
                    n2++;
                }
                break;
            case 3:
                cout << a[i] << "+" << b[i] << "-" << d[i] << "-" << e[i] << "=" << endl;
                cout << "请输入结果:" << endl;
                cin >> result;
                if (result == a[i] + b[i] - d[i] - e[i])
                {
                    cout << "回答正确!" << endl;
                    n1++;
                }
                else
                {
                    cout << "回答错误!" << endl;
                    cout << "正确结果为：" << a[i] + b[i] - d[i] - e[i] << endl;
                    n2++;
                }
                break;
            case 4:
                cout << a[i] << "+" << b[i] << "+" << d[i] << "-" << e[i] << "=" << endl;
                cout << "请输入结果:" << endl;
                cin >> result;
                if (result == a[i] + b[i] + d[i] - e[i])
                {
                    cout << "回答正确!" << endl;
                    n1++;
                }
                else
                {
                    cout << "回答错误!" << endl;
                    cout << "正确结果为：" << a[i] + b[i] + d[i] - e[i] << endl;
                    n2++;
                }
                break;
            case 5:
                if (neg == 0)//结果没有负数
                {
                    if (a[i]<b[i])
                    {
                        t = a[i];
                        a[i] = b[i];
                        b[i] = t;
                    }
                    cout << a[i] << "-" << b[i] << "*" << c[i] << "+" << d[i] << "/" << e[i] << "=" << endl;
                    cout << "请输入结果:" << endl;
                    cin >> result;
                    if (result == a[i] - b[i] * c[i] + d[i] / e[i])
                    {
                        cout << "回答正确!" << endl;
                        n1++;
                    }
                    else
                    {
                        cout << "回答错误!" << endl;
                        cout << "正确结果为：" << a[i] - b[i] * c[i] + d[i] / e[i] << endl;
                        n2++;
                    }
                    break;
                }

                else if (neg == 1)//结果有负数
                {
                    cout << a[i] << "-" << b[i] << "*" << c[i] << "+" << d[i] << "/" << e[i] << "=" << endl;
                    cout << "请输入结果:" << endl;
                    cin >> result;
                    if (result == a[i] - b[i] * c[i] + d[i] / e[i])
                    {
                        cout << "回答正确!" << endl;
                        n1++;
                    }
                    else
                    {
                        cout << "回答错误!" << endl;
                        cout << "正确结果为：" << a[i] - b[i] * c[i] + d[i] / e[i] << endl;
                        n2++;
                    }
                    break;
                }

            case 6:
                cout << a[i] << "*" << b[i] << "*" << d[i] << "/" << e[i] << "=" << endl;
                cout << "请输入结果:" << endl;
                cin >> result;
                if (result == a[i] * b[i] * d[i] / e[i])
                {
                    cout << "回答正确!" << endl;
                    n1++;
                }
                else
                {
                    cout << "回答错误!" << endl;
                    cout << "正确结果为：" << a[i] * b[i] * d[i] / e[i] << endl;
                    n2++;
                }
                break;
            case 7:
                if (b[i] == 0)//分母为零则不计入总数
                {
                    i = i - 1; break;
                }
                else if (remainder == 0)//除法没有余数
                {
                    if (a[i] % b[i] == 0)
                    {
                        cout << a[i] << "/" << b[i] << "=" << endl;
                        cout << "请输入结果:" << endl;
                        cin >> result;
                        if (result == a[i] / b[i])
                        {
                            cout << "回答正确!" << endl;
                            n1++;
                        }
                        else
                        {
                            cout << "回答错误!" << endl;
                            cout << "正确结果为：" << a[i] / b[i] << endl;
                            n2++;
                        }
                        break;
                    }
                    else
                    {
                        i = i - 1; break;
                    }
                }
                else if (remainder == 1)//除法有余数
                {
                    if (a[i] % b[i] != 0)
                    {
                        cout << a[i] << "/" << b[i] << "=" << endl;
                        cout << "请输入结果:" << endl;
                        cin >> result;
                        if (result == (double)a[i] / b[i])
                        {
                            cout << "回答正确!" << endl;
                            n1++;
                        }
                        else
                        {
                            cout << "回答错误!" << endl;
                            cout << "正确结果为：" << (double)a[i] / b[i] << endl;
                            n2++;
                        }
                        break;
                    }
                    else
                    {
                        i = i - 1; break;
                    }
                }

            }
            break;//跳出循环
        }
    }
    cout << "您一共答对" << n1 << "道题目" << endl;
    cout << "您一共答错" << n2 << "道题目" << endl;
    return 0;
}
void main()
{
    int number;//题目数量
    int mul;//乘除法
    int num;//数值范围
    int neg;//负数
    int remainder;//余数
    int c;//循环变量
    
        srand((unsigned)time(NULL));//调用随机函数发生器
        cout << "---------------------------------" << endl;
        cout << "|            四则运算            |" << endl;
        cout << "---------------------------------" << endl;
        cout << "请输入要打印的题目数量：" << endl;
        cin >> number;

        while (number<0)
        {
        cout << "输入错误！" << endl;
        cout << "请输入要打印的题目数量：" << endl;
        cin >> number;
        }

        cout << "是否有乘除法(0表示没有；1表示有)" << endl;
        cin >> mul;
        while (mul != 0 && mul != 1)
        {
            cout << "输入错误，请重新输入！是否有乘除法(0表示没有；1表示有)" << endl;
            cin >> mul;
        }
        if (mul == 1)
        {
            cout << "除法有无余数(0表示没有；1表示有)" << endl;
            cin >> remainder;
            while (remainder != 0 && remainder != 1)
            {
                cout << "输入错误，请重新输入！除法有无余数(0表示没有；1表示有)" << endl;
                cin >> remainder;
            }
        }
        cout << "请输入正整数的数值范围(即最大数)：" << endl;
        cin >> num;
        cout << "减法有无负数(0表示没有；1表示有)" << endl;
        cin >> neg;
        while (neg != 0 && neg != 1)
        {
            cout << "输入错误，请重新输入！" << endl;
            cout << "减法有无负数(0表示没有；1表示有)" << endl;
            cin >> neg;
        }
        display(number, mul, num, neg, remainder);
        cout << "继续请输入1，退出请输入0" << endl;
        cin >> c;
}

设计思路：

本次实验的主要功是：能够判定用户的输入答案是否正确和能够处理四种运算的混合运算。这两个基本要求基本都可以实现，虽然实现的方法比较笨重，就是各自分别计算结构，然后再判断是否正确。这次实验没有实现括号的功能，本想运用递归的思想，把两个操作数的运算看成一个操作数，然后再参与运算，直到满足功能需求，但是这个想法没有实现，还有一个问题就是：括号问题，不知道怎么用合适的方法把括号添加到运算式中，最后也没有想到比较合适的方法。总之，这次实验还是很费力的，花费的时间也很长，但是自己也没有比较好的完成。

工作照片：

周活动总结表：

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