1、无源汇可行流
对每条边(from,to,cap)改造
cap=upper-lower
inflow[to]+=lower
outflow[from]+=lower
然后对每个点Addedge(s,i,inflow[i]),Addedge(i,t,ouflow[i])
#include<iostream> #include<cstdio> #include<cstring> #include<vector> #include<queue> using namespace std; const int maxn=30000; const int oo=1000000000; int n,m; int inflow[maxn],outflow[maxn]; struct Edge{ int from,to,cap,flow; }; vector<int>G[maxn]; vector<Edge>edges; void Addedge(int x,int y,int z){ Edge e; e.from=x;e.to=y;e.cap=z;e.flow=0; edges.push_back(e); e.from=y;e.to=x;e.cap=0;e.flow=0; edges.push_back(e); int c=edges.size(); G[x].push_back(c-2); G[y].push_back(c-1); } int s,t; queue<int>q; int vis[maxn]; int d[maxn]; int Bfs(){ memset(vis,0,sizeof(vis)); vis[s]=1;d[s]=0;q.push(s); while(!q.empty()){ int x=q.front();q.pop(); for(int i=0;i<G[x].size();++i){ Edge e=edges[G[x][i]]; if((e.cap>e.flow)&&(!vis[e.to])){ vis[e.to]=1; d[e.to]=d[x]+1; q.push(e.to); } } } return vis[t]; } int Dfs(int x,int a){ if((x==t)||(a==0))return a; int nowflow=0,f=0; for(int i=0;i<G[x].size();++i){ Edge e=edges[G[x][i]]; if((d[x]+1==d[e.to])&&((f=Dfs(e.to,min(a,e.cap-e.flow)))>0)){ nowflow+=f; a-=f; edges[G[x][i]].flow+=f; edges[G[x][i]^1].flow-=f; if(a==0)break; } } return nowflow; } int Maxflow(){ int flow=0; while(Bfs())flow+=Dfs(s,oo); return flow; } int Lo[maxn]; int main(){ scanf("%d%d",&n,&m); for(int i=1;i<=m;++i){ int x,y,l,h; scanf("%d%d%d%d",&x,&y,&l,&h); Addedge(x,y,h-l); inflow[y]+=l; outflow[x]+=l; Lo[i*2-2]=l; } s=n+1;t=s+1; for(int i=1;i<=n;++i)Addedge(s,i,inflow[i]); for(int i=1;i<=n;++i)Addedge(i,t,outflow[i]); Maxflow(); int fla=1; for(int i=0;i<G[s].size();++i){ Edge e=edges[G[s][i]]; if(e.cap!=e.flow)fla=0; } if(fla){ printf("YES "); for(int i=0;i<m+m;i+=2){ printf("%d ",edges[i].flow+Lo[i]); } }else{ printf("NO "); } return 0; }
2、
有源汇可行流
Addedge(t,s,+oo)
然后转化为无源汇可行流
3、
有源汇最大流
先求出可行流
然后跑s->t的最大流就为答案
#include<iostream> #include<cstdio> #include<cstring> #include<vector> #include<queue> using namespace std; const int maxn=100009; const int oo=1000000000; int ss,tt; int n,m; int inflow[maxn],outflow[maxn],suminflow=0; struct Edge{ int from,to,cap,flow; }; vector<int>G[maxn]; vector<Edge>edges; void Addedge(int x,int y,int z){ Edge e; e.from=x;e.to=y;e.cap=z;e.flow=0; edges.push_back(e); e.from=y;e.to=x;e.cap=0;e.flow=0; edges.push_back(e); int c=edges.size(); G[x].push_back(c-2); G[y].push_back(c-1); } int s,t; queue<int>q; int vis[maxn]; int d[maxn]; int Bfs(){ memset(vis,0,sizeof(vis)); vis[s]=1;d[s]=0;q.push(s); while(!q.empty()){ int x=q.front();q.pop(); for(int i=0;i<G[x].size();++i){ Edge e=edges[G[x][i]]; if((e.cap>e.flow)&&(!vis[e.to])){ vis[e.to]=1; d[e.to]=d[x]+1; q.push(e.to); } } } return vis[t]; } int Dfs(int x,int a){ if((x==t)||(a==0))return a; int nowflow=0,f=0; for(int i=0;i<G[x].size();++i){ Edge e=edges[G[x][i]]; if((d[x]+1==d[e.to])&&((f=Dfs(e.to,min(a,e.cap-e.flow)))>0)){ nowflow+=f; a-=f; edges[G[x][i]].flow+=f; edges[G[x][i]^1].flow-=f; if(a==0)break; } } return nowflow; } int Maxflow(){ int flow=0; while(Bfs())flow+=Dfs(s,oo); return flow; } int main(){ scanf("%d%d%d%d",&n,&m,&ss,&tt); s=n+1;t=s+1; for(int i=1;i<=m;++i){ int x,y,lo,hi; scanf("%d%d%d%d",&x,&y,&lo,&hi); Addedge(x,y,hi-lo); inflow[y]+=lo; outflow[x]+=lo; suminflow+=lo; } for(int i=1;i<=n;++i){ Addedge(s,i,inflow[i]); Addedge(i,t,outflow[i]); } Addedge(tt,ss,oo); if(Maxflow()!=suminflow){ printf("please go home to sleep "); }else{ s=ss;t=tt; printf("%d ",Maxflow()); } return 0; }
4、有源汇上下界最小流
先跑可行流
然后把t->s的边删掉
在跑t->s的最大流
用t->s的边的流量- t->s的最大流
#include<iostream> #include<cstdio> #include<cstring> #include<vector> #include<queue> using namespace std; const int maxn=50009; const int oo=1000000000; int n,m,ss,tt; int inflow[maxn],outflow[maxn],suminflow; struct Edge{ int from,to,cap,flow; }; vector<int>G[maxn]; vector<Edge>edges; void Addedge(int x,int y,int z){ Edge e; e.from=x;e.to=y;e.cap=z;e.flow=0; edges.push_back(e); e.from=y;e.to=x;e.cap=0;e.flow=0; edges.push_back(e); int c=edges.size(); G[x].push_back(c-2); G[y].push_back(c-1); } int s,t; queue<int>q; int vis[maxn]; int d[maxn]; int Bfs(){ memset(vis,0,sizeof(vis)); vis[s]=1;d[s]=0;q.push(s); while(!q.empty()){ int x=q.front();q.pop(); for(int i=0;i<G[x].size();++i){ Edge e=edges[G[x][i]]; if((e.cap>e.flow)&&(!vis[e.to])){ vis[e.to]=1; d[e.to]=d[x]+1; q.push(e.to); } } } return vis[t]; } int Dfs(int x,int a){ if((x==t)||(a==0))return a; int nowflow=0,f=0; for(int i=0;i<G[x].size();++i){ Edge e=edges[G[x][i]]; if((d[x]+1==d[e.to])&&((f=Dfs(e.to,min(a,e.cap-e.flow)))>0)){ nowflow+=f; a-=f; edges[G[x][i]].flow+=f; edges[G[x][i]^1].flow-=f; if(a==0)break; } } return nowflow; } int Maxflow(){ int flow=0; while(Bfs())flow+=Dfs(s,oo); return flow; } int main(){ scanf("%d%d%d%d",&n,&m,&ss,&tt); for(int i=1;i<=m;++i){ int x,y,lo,hi; scanf("%d%d%d%d",&x,&y,&lo,&hi); inflow[y]+=lo; outflow[x]+=lo; Addedge(x,y,hi-lo); suminflow+=lo; } s=n+1;t=s+1; Addedge(tt,ss,oo); for(int i=1;i<=n;++i){ Addedge(s,i,inflow[i]); Addedge(i,t,outflow[i]); } if(Maxflow()!=suminflow){ printf("please go home to sleep "); }else{ int tm; s=ss;t=tt; for(int i=0;i<G[t].size();++i){ Edge e=edges[G[t][i]]; if(e.to==s&&e.cap==oo){ tm=edges[G[t][i]].flow; edges[G[t][i]].flow=edges[G[t][i]].cap=0; edges[G[t][i]^1].flow=edges[G[t][i]^1].cap=0; } } swap(s,t); printf("%d ",tm-Maxflow()); } return 0; }