题目描述
大家都知道斐波那契数列,现在要求输入一个整数n,请你输出斐波那契数列的第n项(从0开始,第0项为0)。
n<=39
有多种方法,简单的循环、递归、动态规划;
1 class Solution01 { 2 public: 3 int Fibonacci(int n) { 4 int a = 0, b = 1, c; 5 for (int i = 2; i <= n; ++i) 6 { 7 c = a + b; 8 a = b; 9 b = c; 10 } 11 return n == 0 ? 0 : b; 12 } 13 }; 14 15 class Solution02 { 16 public: 17 int Fibonacci(int n) { 18 if (n <= 1) 19 return n; 20 return Fibonacci(n - 1) + Fibonacci(n - 2); 21 } 22 }; 23 24 class Solution03 { 25 public: 26 int Fibonacci(int n) { 27 if (n <= 1) 28 return n; 29 vector<int>dp(n + 1); 30 dp[0] = 0, dp[1] = 1; 31 for (int i = 2; i <= n; ++i) 32 dp[i] = dp[i - 1] + dp[i - 2]; 33 return dp[n]; 34 } 35 };