• 软件测试(四)


    第三次作业

    Use the following method printPrimes() for questions a–d.

    程序如下:

    /******************************************************* 
         * Finds and prints n prime integers 
         * Jeff Offutt, Spring 2003 
         ******************************************************/ 
        public static void printPrimes (int n) 
        { 
            int curPrime; // Value currently considered for primeness 
            int numPrimes; // Number of primes found so far. 
            boolean isPrime; // Is curPrime prime? 
            int [] primes = new int [MAXPRIMES]; // The list of prime numbers. 
            
            // Initialize 2 into the list of primes. 
            primes [0] = 2; 
            numPrimes = 1; 
            curPrime = 2; 
            while (numPrimes < n) 
            { 
                curPrime++; // next number to consider ... 
                isPrime = true; 
                for (int i = 0; i <= numPrimes-1; i++) 
                { // for each previous prime. 
                    if (isDivisable(primes[i],curPrime)) 
                    { // Found a divisor, curPrime is not prime. 
                        isPrime = false; 
                        break; // out of loop through primes. 
                    } 
                } 
                if (isPrime) 
                { // save it! 
                    primes[numPrimes] = curPrime; 
                    numPrimes++; 
                } 
            } // End while 
            
            // Print all the primes out. 
            for (int i = 0; i <= numPrimes-1; i++) 
            { 
                System.out.println ("Prime: " + primes[i]); 
            } 
        } // end printPrimes

    a、画出数据流图:

    b、测试用例t1=(n=3)和t2=(n=5),t2会发现但是t1不会发现的错误。

      数组越界问题。

    c、找到一个测试用例不经过while循环

        当n=1时即可满足

    d、找出节点覆盖(node coverage)

      {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16}

      边覆盖(edge coverage)

      {(1,2),(2,3),(3,4),(4,5),(5,6),(5,8),(6,7),(6,10),(7,8),(8,9),(8,11),(9,2),(10,5),(11,2),(2,12),(12,13),(13,16),(13,14),(14,15),(15,13)}

      主路径覆盖

      {(1,2,3,4,5,6,10),(1,2,3,4,5,6,7,8,9),(1,2,3,4,5,6,7,8,11),(1,2,12,13,14,15),(2,3,4,5,6,7,8,9,2),(2,3,4,5,6,10),(2,3,4,5,6,7,8,11,2),(5,6,10,5),(5,6,7,8,5),(5,6,7,8,11,2,3,4,5),(5,6,7,8,9,2,3,4,5),(5,6,7,8,9,2,12,13,14,15),(5,6,7,8,9,2,12,13,16),(6,10,5,6),(6,7,8,9,2,3,4,5,6),(6,7,8,11,2,3,4,5,6),(7,8,9,2,3,4,5,6,7),(7,8,11,2,3,4,5,6,7),(8,5,6,7,8),(8,9,2,3,4,5,6,7,8)(8,11,2,3,4,5,6,7,8),(9,2,3,4,5,6,7,8,9),(10,5,6,10)(11,2,3,4,5,6,7,8,11),(11,2,3,4,5,6,10),(11,2,3,4,5,6,7,8,9),(1,2,12,13,14,15),(1,2,12,13,16),(13,14,15,13),(14,15,13,16)}

      

    主路径覆盖的测试:

    测试用例如下(代码中一部分是为了做测试用的,未删除):

    package printPrimes;
    
    import static org.junit.Assert.*;
    
    import org.junit.Test;
    
    public class test_primes {
    
        @Test
        public void test() {
    
            //printPrimes p = new printPrimes();
            int []num = printPrimes.printPrimes(3);
            for(int i = 0; i < 100; i++)System.out.println(num[i]);
            int [] num1 = new int[100];
            num1[0] = 2;num1[1]=3;num1[2]=5;
            for(int i = 3; i < 100; i++ ){
                num1[i] = 0;
            }
        
            assertArrayEquals(num1,num); 
        }
    
    }

    结果:

    即可完成主路径的覆盖。

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  • 原文地址:https://www.cnblogs.com/zyqBlog/p/5330094.html
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