• LOJ#2471「九省联考 2018」一双木棋 MinMax博弈+记搜


    题面

    戳这里

    题解

    因为每行取的数的个数是单调不增的,感觉状态数不会很多?

    怒而记搜,结果过了...

    #include<bits/stdc++.h>
    #define For(i,x,y) for (int i=(x);i<=(y);i++)
    #define Dow(i,x,y) for (int i=(x);i>=(y);i--)
    #define cross(i,k) for (int i=first[k];i;i=last[i])
    using namespace std;
    typedef long long ll;
    typedef unsigned long long ull;
    inline ll read(){
        ll x=0;int ch=getchar(),f=1;
        while (!isdigit(ch)&&(ch!='-')&&(ch!=EOF)) ch=getchar();
        if (ch=='-'){f=-1;ch=getchar();}
        while (isdigit(ch)){x=(x<<1)+(x<<3)+ch-'0';ch=getchar();}
        return x*f;
    }
    const int N = 15;
    int n,m,a[N][N],b[N][N];
    map<ull,int>Map;
    int now[N];
    const ull base = 233;
    inline ull Get(){
        ull ans=0;
        For(i,1,n) ans=ans*base+now[i];
        return ans; 
    }
    inline int dfs(int x){
        ull hsh=Get();
        if (Map.count(hsh)) return Map[hsh];
        int tmp=(!x)?-1e9:1e9;
        For(i,1,n) 
            if (now[i]+1<=now[i-1]){
                now[i]++;
                if (x>0) tmp=min(tmp,dfs(x^1)-b[i][now[i]]);
                    else tmp=max(tmp,dfs(x^1)+a[i][now[i]]);
                now[i]--;
            }
        return Map[hsh]=tmp;
    }
    int main(){
         n=read(),m=read();
         For(i,1,n)
         	For(j,1,m) a[i][j]=read();
         For(i,1,n)
         	For(j,1,m) b[i][j]=read();
         For(i,1,n) now[i]=m;
         Map[Get()]=0,memset(now,0,sizeof now),now[0]=m;
         printf("%d",dfs(0));
    }
    
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  • 原文地址:https://www.cnblogs.com/zykykyk/p/9489912.html
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